Answer / hussain

Volume of 1 Brick = 0.230*0.115*0.075 = 0.002
So No of brick req for 1 m3 = (1/0.002) = 500 Nos

1.7 bag of Cement required

0.31 cum sand required for 1 cum of brickwork

Answer / raja j

brick size in meter=.23*.115*.075 =.0019
add 10 mm mortar for ech sides=(.24*.125*.085)=(.0025)

bricks required for 1 m3 =(1/(0.0025)=400 nos

mortar required =(.0025-.0019)*400=.24

add 15% for wastage = (.24*1.15)=.276m3

so required sand is =.276 m3

cement is =(1440/6)=240*.276= 66 kg

Answer / ajeet kumr bhatnagar

Actual brick size 230*115*76

So No's of bricks in 1 m3=1÷.23*.115*.076=498nos
Now consider 10mm thick mortar
Now bricks size =240*125*86cm
No's of bricks in 1m3=1/.24*.125*.86=388nos
5% wastge=388+20=418nos actual
Mortar 498-388=110nos bricks
=110*.23*.115*.076=.22m3
30% for dry volume=0.286m3
Wastage 5%=0.015
Net volume=.286+.015=.3(approx)
Cement=.3÷7=0.042=.042÷.0345=1.24 bags

Sand=.042*6=.252m3 or.252*35.28=8.89cft

Answer / tipu sultan

standard size of brick
=(.19×.09×.09)m

volume of brick
=(.19×.09×.09)m^3
=0.001539
=0.00154m^3

with mortar brick size
=(.20×.10×.10)m
& volume=
=(.20×.10×.10)m^3
=0.002m^3

for volume 0.002m^3 then no. of brick=1

so that
for 1m^3 then nos. of brick = 1÷.002 = 500nos.

Answer / ajeet kumar bhatnagar

consider brick joint 10mm.
Brick volume 0.23x0.115x0.76=.0020m3
So for 1m3 brick work brick required=1/.0020=500nos
Now taking joint ,volume =.240x.125x0.086=.00245
Now for 1m3 brick work brick require=1/.00258= 388nos
So mortar volume =500-388=112nos brick=112x0.0020=0.32m3
For 1:6 mortar Cement 1/7x0.320=0.0457m3=0.00457/0.0345=1.32bags=1.32x50=66 kg
Sand=6/7x0.32=.274m3x35.28=9.67cft

Answer / md.furqan anasri

Bricks :395
Cement:1.25 Bags (CPWD)
C-sand:10 cft

Answer / guest

500 bricks,

Answer / b.jagan

Per 1m3 B.W required materials
Brick=500mom's
Cement=75kg
Sand=10.5cft

Answer / asmar ahmed

cement = 1.40 Bags
sand = 10.50 Cft
Bricks = 466 Nos

Answer / saeed khan

Brick=500
Sand=.257
Cement=1.225 bags

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