Answer / bala ganesh

TOTAL QUANTITY OF PLASTERING=3.05*3.05*.01=.093 cu.m
by thumb rule
.75 cu.m of plastering requires =350kg of cement
1750 kg of sand for
the ratio of 1:5 (the weights are calculated with specific
gravities) from this


add 30% extra for wastage and uneveness=.121 cu.m
so for .121 cu.m of plaster requires = 56.5 kg of cement
282.5 kg of sand

Answer / viplav

breath*depth*0.85/fy.

Answer / rustam sahu

Suppose we have a room size of 10 ft. x 10 ft. where height of room is 11 feets and width of plastering is 1/2 inch.
1/2 inch = 1/2 divided by 12 = 0.04167 feet
now, let us find out the wet volume for plastering just for one side of wall..
i.e., (length x width x height ) =
= 10 x 0.04167 x 11
= 4.583 c.ft.
for dry volume, segregation value 1.52
Dry volume = wet vol. x seg. value
= 4.583 x 1.52
= 6.97 c.ft.
also, plastering ratio (1:6) sum of ratio = 1+6= 7
per quantity = dry vol. divided by sum of ratio
i.e., = 6.97 / 7 = 0.9957
note: 1 bag cement carries 1.25 c.ft
for cement per bag = 0.9957 /1.25 = 0.7965 bag (for 1 wall)
since a room have 4 walls. so,
0.7965 x 4 = 3.1862 bag
add 10% extra for irregularities at joints or corners
i.e., 3.186 + 0.3186 = 3.5 bags
for sand = per quantity x per ratios x no. of walls
= 0.9957 x 6 x 4
= 23.8968 c.ft

Answer = a room size (10 x 10) ft. having 11 feets height and 1/2 inch width of plastering will required 3.50 bag of cement and 23.89 c.ft. of sand

Answer / sunandan sharma

10feet = 10/3.28=3.048m
volume = 3.048x3.048x.01=.093 cubic meter
for dry material factor is 1.2
so quantity of dry material=0.093x1.2= 0.11cum
now the ratio is (1:5)
so cement=0.11/6 =0.018cum=0.64(.018x28.8bags)
=0.518bags=25.92kg
sand=0.018x5=0.09cum=3.17cuft

Answer / amir shahzad

plaster area =100

thikh of plaster=10mm

plaster voleem=1/2x1/12x1oo=1.5

dry metreal one cft = 4.166
1.5x4.166=6.249
ratio 1:4=5

fromula = 6.249x1/5=1.25/1.24=0.99 cement bage

6.249x4/5=4.99 send

Answer / anant dawale

For 100 sqft;(9.295 m2)Plastering
3.0488m x3.0488m ;Thickness=0.02m (20mm)
Dry volume of mortar= 3.048 x 3.048 x.02= 0.1859 m3
Wet volume of mortar (30%) = 0.1859 x 1.3= 0.2416 m3
Mortar Proportion =1:5.
Volume of Cement= Wet volume /(1+5)i.e .02416/6=0.0403 m3

Qty of Sand=0.0403 X 5 = 0.201 m3.
Volume Of Cement/Bag= 0.034 m3
i.e.for 1 Bag of Cement ; Sand = 0.17 m3

Answer / aravinth

Cement mortar 1:2 - 1m3
How much of cement
How much of sand
How much of water

Answer / harish po

100sqm,12mm thick,CM 1:4 plastering
volume = 100x(12/1000)=1.20 cum
Add 30% as bulking of sand=(1.2x30)/100=0.360 cum
Add 20% as wastage =((1.2+0.36)x20)/100=0.312 cum
Total=1.872 cum
volume of mortar=1.872/(1+4) =0.374 cum

volume of cement = 0.374 cum x 30 bag/cum =10.77 bag
10.77 bag x 50 kg/bag =538.5 kg for 100 sqm
(for 1sqm 12mm thick,CM 1:4 cement required=5.385kg)

volume of sand = 0.374 x 4 (CM 1:4) =1.496 cum for 100 sqm
(for 1sqm 12mm thick,CM 1:4 sand required=0.01496 cum/0.53cft)

Answer / ashok

If we Consider 12 mm thick plaster(1:6)

Area for Calculation=1M x 1M = 1 Sqm

Quantity in Cum.=1M x 1M x 0.012M = 0.012 Cum.

Proportion of Cement = [1/7=0.143 x 0.012=0.002 Cum/0.035 x 50 = 2.45 K.g

Add 25%+5% [Dry volumn + Wastage] =[ 2.45 x 30% = 3.18 K.g]

Proportion of Send = [6/7=0.857 x 0.012=0.010 Cum x 35.32 = 0.363 cft

Add 25%+5% [Dry volumn + Wastage] =[ 0.363 x 30% = 0.472 cft]

Answer / ashok sharma

If we Consider 12 mm thick plaster(1:6)

Area for Calculation=1M x 1M = 1 Sqm

Quantity in Cum.=1M x 1M x 0.012M = 0.012 Cum.

Proportion of Cement = [1/7=0.143 x 0.012=0.002 Cum/0.035 x 50 = 2.45 K.g

Add 25%+5% [Dry volumn + Wastage] =[ 2.45 x 30% = 3.18 K.g]

Proportion of Send = [6/7=0.857 x 0.012=0.010 Cum x 35.32 = 0.363 cft

Add 25%+5% [Dry volumn + Wastage] =[ 0.363 x 30% = 0.472 cft]

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