Answer / toss

IN answer no 1 quantity of cement value is 0.02.. then why u multiply 0.02 with sand

Answer / vijay govardhane

Total area plaster: 3.05*3.05=9.3
(Convert area into sq.f):9.3*10.75=99.97
100/99.97=.9997(1 bag)..cement
..sand=99.97/100=.997
=.9997/17=0.058...brass
(17 is a standerd value of sand In single coat =17 cu.m)

Answer / rakesh kumar sinha

Total Plaster Qty.=.09cum
Cement 1cum=1440
Sand 1cum=1600
Ratio of cement and sand=1:5
so,
cement ratio=.02
sand ratio=.08
cement required
1440*.02=28.8kg
sand required
1600*.08=128kg

Answer / shaik's construction

For a wall of 10'x10' ( i.e LxH) Having 10mm thicness
mortar ratio 1:6
10' approx equal to 3m
vol of mortar = 3*3*0.01
               =0.09cum
vol of cement = 1*0.09/(1+6)
              =0.01286cum        :-(cement for 1cum=1440kg)
:-amount of cement=0.01286*1440
                  =18.5kg.
amount of sand=18.5*6=111kg

Answer / anoop didwaniya

10'X10'=100 sft.
converted in to sqm.=100/10.76=9.29 sqm.
ratio= 1:5, 1+5=6
for cement----1/6 x 1.52=.25 m3 x 35.28=8.93/1.25=7.15
so 7.15 bag in a cum. so for 20mm thk.
for cum. 9.29 sqm x .020 mm = .18 cum.
therefore --7.15 x .18m3 = 1.28 bag answer
for sand------5/6 x 1.52=1.26 m3 x 35.28=44.68 cft./1cum.
so 44.68 x .18m3 = 8 cft answer
1.28 bag of cement
8 cft of sand. required in 10'10 wall with 20mm thk.

Answer / risadh

Formula=Volume*Density of material
Add- Shirinkage-35%to40%
Volume= plastering volume+Depression,joint&Wastage
Density=Cement-1440Kg/m3,Sand-1600Kg/m3
Shirinkage-35%to40%
Depression,joints&Wastage normally-20%of plastering Volume
Cement=(1/6*0.11124*1440)+(1/6*0.11124*1440)35%=
Sand=(5/6*0.11124*1600)+(5/6*0.11124*1600)35%=

Answer / jehan abid

how to calculate the cement sand and crush quantity in 6 inch slab?

Answer / rakesh sinha

Total Plaster Qty.=.09cum
Wastage 20%=.02cum
Total Qty.= .11
Cement 1cum=1440
Sand 1cum=1600
Ratio of cement and sand=1:5
so,
cement ratio=.0186
sand ratio=.0929
cement required
1440*.0186=26.76kg
sand required
1600*.0929=148.65kg

Answer / waseem ahmed

10' X 10' X 0.03937" = 3.937

1:5= 1+5 = 6 therefore

3.937 / 6 = 0.656 cft cement

3.937 X 5 = 19.67 cft sand

will be used to plaster your area

Answer / sabeehullah

10*10*.032=3.2
1+5=6
sum of ratio = 6
constant of cement per bag in cft = 1.25
1/6 = .166*1.54 = .255/1.25=.204 say half bag

In which grade of steel the laping length required is more,Fe 415 or Fe 500 ? and why?

1 Answers  

What is the difference between oneway slab and twoway slabs

2 Answers  

How many bags of cement will be required for 45.5 M^3 Concrete with the ratio of 1 Cement+1 Crash+ 2 Sand+1 Gravel?

0 Answers   First MicroFinance Bank FMFB,

please what is the number of bars required for a column of 6mx6m and 450mmx300mm,its a commercial building (Church)

0 Answers  

how much sand requires for Light weight blocks for 100sqft

1 Answers   Bahria Town, NCC,

state the main objectives of underpinning

4 Answers  

How Can Calculate Plastering Quantities For 260.04 square meter by using CM 1:4 with 25mm Thick ?

2 Answers  

How do you find the difference between 53&43 grade cement in site?

6 Answers   L&T,

how many AAC blocks of size 600*200*225 mm are required for 1 cu.m of area

1 Answers  

What is the roll of face bars in beams

2 Answers  

If we don't have drawing for Excavation of building,At what rule we will go for excavation and how much depth will go for a villa?

0 Answers   Jain Housing,

Analyze the rate for 1st class brick work in superstructure with 1:6 cement sand mortar. Consider 1000 cu.ft quantity and work out the rate per cu.ft

0 Answers