How to calculate the cement, sand quantity for plastering?
(10'x10')10mm thick ratio 1:5. wht"s the formula?
Answers were Sorted based on User's Feedback
Answer / santosh singh
10 feet= 3.05m
area of plaster = 3.05 x 3.05 = 9.3 m2
(convert thickness of plaster into m divide by 1000)
volume of plaster = 9.3 x (10/1000) = 0.09 m3
quantity of cement = 0.09/1+5 =0.09/6 = 0.02 m3
as cement comes in bags of 50 kg therefore volume of one
bag cement = o.0347 m3 (exact)
(or it may be taken 0.034 or 0.035 m3)
no. of cement bags = 0.02/0.0347 = 0.58 bags (almost 1 bag
of cement required for plaster )
quantity of sand = 0.02 x 5 = 0.10 m3
this is exact calculation
you can add 30% extra for wastage etc.
|Is This Answer Correct ?||688 Yes||187 No|
Answer / srikanth
as per thumb rule 1:5 CM
since wall is un-uniform ,increase by 30% ie
.092412 + .0277248= 0.120 cu.m
dry volume increses by 25% = 0.12 + .03 = 0.15 cu.m
total volume of mor= 0.15/6 = .025 cu.m
of cement =0.025x 1440= 36 kg cement
sand = 0.025 X 6= 0.15 cu.m
|Is This Answer Correct ?||217 Yes||96 No|
Answer / aijaz hussain, modi builders
Volume of Wet Mortar = 10 mm X 100 sft.
= 10/1000 X 100/10.76 = 0.093 cu.m.
Add 20% for depressions, joints and wastage
= 0.0186 + 0.093 = 0.112 cu.m.
Volume of Dry Mortar = 1.3 X 0.112 = 0.146 cu.m.= 5.154 cu.ft.
Cement required = 1/6 X 0.146 = 0.024 cu.m. = 0.7 Bag
Sand required = 5/6 X 0.146 = 0.122 cu.m. = 4.30 cu.ft.
|Is This Answer Correct ?||117 Yes||50 No|
Answer / abid nawaz
10' x 10' x 0.0333'
Dry metarial in one cft = 1.27 cft
3.33 x 1.27
sum of ratio = 1+5 = 6
quantity of cement = 1*4.229/6
= 0.7048 cft
volume of one bag = 1.25 cft
=0.56 cement bag
quantity of sand = 5*4.229/6
= 3.524 cft
|Is This Answer Correct ?||76 Yes||18 No|
Answer / sri
1/6=.1666+25%+30%=.71cu.m of cement
|Is This Answer Correct ?||125 Yes||96 No|
Answer / manoj kumar moharana
cement mortar ratio is (1:5)
assume the area that we are going to calculate the plaster qty is,
L = 3.048 m
B = 3.048 m
given H = 10 mm = 0.01 m
hence the qty is = 3.048 x 3.048 x 0.01 = 0.093 cum
add 30% of the above qty for joints = 0.093 x 0.3 = 0.028
total qty = 0.093+0.028
add more 25% for dry volume = 0.121 x 0.25 = 0.03
total qty =0.121+0.03= 0.151 cum
no. of cement bags = 0.151/(1+5) =0.025 cum / 0.0347= 0.720 bags
= 1 apprx.( where as 0.0347 is the volume of 1 bag cement)
qty of sand = 0.025 cum x 5 = 0.125 cum
therefore mortar reqd. for 1:5 cement plaster is
cement = 0.025 cum = 0.720 bag
& sand= 0.125 cum
|Is This Answer Correct ?||28 Yes||5 No|
Answer / linu t mathew
Area to be plastered = 10'*10' = 100'
= 100/10.76 = 9.29sqm
(ie; 1 sqm = 10.76 sqft)
Thickness of mortar layer = 10mm = 0.010m
Volume of mortar required = 9.29*0.010 = 0.09cum
Add 15% for allallowance for calculation of surface and
wastages = (15/100)*.09 = 0.013 cum
Therefore, total volume of mortar required = .09+0.013 =
0.103 cum, say 0.10cum
Sand required for 0.10cum of CM 1:5 = 0.10 cum
Cement required for 0.10 cum of CM 1:5 = (1440/5)*0.10
= 288*0.10 = 28.8 kg
(ie; 1 cum of cement weighs 1440 kg)
|Is This Answer Correct ?||42 Yes||25 No|
Answer / naga
1/6=.1666+25%+30%=.71cu.m of cement
|Is This Answer Correct ?||17 Yes||9 No|
Answer / ankit kumar
10 feet= 3.048m
Thickness of plaster is 10mm or 0.01m
Volume of plaster = area*thickness
Add 30% to fill up the joint,uneven surface etc
30% of 0.0929m3 = 0.027m3
The quantity of motar=0.0929+0.0279
Increase by 25% the total dry volume
25% of 0.1208m3=0.0302m3
Total dry volume= 0.1208+0.0302
For 1:5 sand motar.
quantity of cement=0.151/(1+5)
And for quantity of sand 0.02517*5=0.12585m3
Density of cement= 1400kg/m3
One bag of cement =50kg
Then volume of one bag cement=50/1400
Now bag of cement=0.02512/0.0375
=0.67 bag i.e almost one bag
|Is This Answer Correct ?||8 Yes||1 No|
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