Answer / b.s.dev

Let the size of brick be 230mm x 115mm x 75mm
Vol. of brick( w/o mortar) = 0.00198 cum.
Thk. of mortar be 12mm.
vol. of brick with mortar = 242mm x 127mm x 87mm
= 0.00267 cum.
No. of bricks in 1 cum. with mortar = 1/0.00267
= 373.99
Say = 374 bricks.
Cement Mortar required = 1-( 374 x 0.00198)cum.
= 0.259 cum.
Say 0.26 cum

Add 15% for frog filling and wastage while execution.
Vol. of wet mortar = 0.299 cum.
Vol. of dry mortar( increase by 30% ) = 0.388 cum.

For CM of 1:6

Qty. of cement = 1/7 x (1440 x 0.388)
= 0.055 cum.
Qty. of sand = 0.055 x 6
= 0.330 cum.

Answer / ar. g.s. rehal

Let the size of brick be 230mm x 115mm x 75mm
Vol. of brick( w/o mortar) = 0.00198 cum.
Thk. of mortar be 12mm.
vol. of brick with mortar = 242mm x 127mm x 87mm
= 0.00267 cum.
No. of bricks in 1 cum. with mortar = 1/0.00267
= 373.99
Say = 374 bricks.
volume of 374 bricks= 374 x 0.00198 = 0.74052cum
Cement Mortar required for 1cum = 1 - 0.74052cum.
= 0.259 cum.
Say 0.26 cum

Add 15% for frog filling and wastage while execution.
.26 x 15/100 = 0.299 cum
Vol. of wet mortar = 0.299 cum.
Vol. of dry mortar( increase by 30% ) 0.299 x 30/100 =0.0897
0.299 + 0.0897 = 0.388 cum.

For CM of 1:6 (1 + 6 = 7)

Qty. of cement for 1cum = 1/7 x 0.388
= 0.055 cum.
Qty. of sand for 1cum = 0.055 x 6
= 0.330 cum.

Qty. of cement for 10cum =10 x 0.055
=0.55 cum.
Qty. of sand for 10cum = 10 x 0.330
= 3.30 cum.

Answer / uday kiran

The size of brick be 230mm x 115mm x 75mm
Vol.of brick( w/o mortar) = 0.00198 cum.
Thk.of mortar be 12mm.
vol.of brick with mortar = 242mm x 127mm x 87mm = 0.00267 cum.
No.of bricks in 1 cum. with mortar = 1/0.00267 = 373.99
Say = 374 bricks.
Cement Mortar required = 1-(374 x 0.00198) cum= 0.259 cum.
Say 0.26 cum
Add 15% for frog filling and wastage while execution.
Vol. of wet mortar = 0.299 cum.
Vol. of dry mortar (increase by 30%) = 0.388 cum.
For CM of 1:6
Qty. of cement = 1/7 x (1440 x 0.388) = 0.055 cum.
Qty. of sand = 0.055 x 6 = 0.330 cum.

Answer / jocky

mortar required for 10 cu.m brick work

Dry mortar = 30% of brick work = 3 cu.m

one part of cement=3cu.m/sum of proportion

(3/1+6)=0.428cu.m

cement required in bags...0.428/vol. of one bag of cement

(0.428/0.035) =12.23 bags ..take 13 bags of cement

sand = 0.428*6= 2.57 cu.m

Answer / sudhir

see CPWD ANALYSIS
480 BRICKS PER CUM I/C WASTAGE
1.24 BAGS CEMENT/CUM I/C WASTAGE
1.24*.035*6 = WILL BE THE QTY OF C.SAND REQD/ PER CUM

Answer / bhupendra potpose

Consumption & Rate analysis Brick Masnory 230mm 1:6
Superstructure With scaffolding

Providing and placing brick work 230mm 1:6 Superstructure
With scaffolding
1.3Ref: use 1..3 standard
Proportion of materials
Cement 1
Sand 6
Total 7
Std constant(1.5) / Total of proporttion(4)
0.186
1) Required volume of cement for 1 cum.

1 Proportion of cement 0.19
Add wastage(2.50%) 0.005
Vol of cement for 1 cum 0.190
0.035 is cum of per 50kg of bags 5.44.

As per standard we assumed that in 1cum of brick work ,the
quantity of mortor (Cement & Sand )is consider in
quantity. (24%) 1.28
Cost of cement per bags 325
Total cost of 1.34 bags 415.39

2) Required volume of Sand for 1 cum

2 Proportionof Sand 1.114
Add wastage(2.50%) 0.028
Vol of Sand for 1 cum 1.142
As per standard we assumed that in 1cum of brick work ,
the quantity of mortor (Cement & Sand )is consider in
quantity.(24%) 0.268
Cost of sand per brass 875
Total cost of 0.284 cum sand 234.85


3)Required brick for 1 cum of size 230x115x75mm

Actual Vol of one bricks is 0.00198cum,&
10 gap Allaround is become 0.00255
Nos of bricks in 1cum0.00255 1 392.16
Add wastage(10.00%) 39.22
Total Required brick for
1 cum 431.37
Cost of bricks 5.00
Total cost of brick 2156.86

A)Total material cost (1+2+3)
2807.10

4)Cost for Manpower ,Mixing ,Shifting ,
placing etc, Rs 15 / sft-Mumbai, 529.80

5) Cost for screeing,
cleaning ,of sand (10%) 333.69
6) Cost for Tools ,
Safety, curing etc(5%) 183.53
B) Cost of labour on
total material cost (4+5+6)
1047.02

C) Cost of Material & labour (A+B) 3854.12

5)Add over head(5%) 192.71
6)Add profit on(15%) 607.02


D- Total of (C+5+6),Over head & profit cost
P/A P230mm,1:6 Per Sqm. 4653.85
If the brick work is required to .


convert into Sqmt
1) for 230mm ; 0.23 1070.39
2) for 115mm ; 0.115 535.19

Answer / arvind vyas

The size of brick be 230mm x 115mm x 75mm
Vol.of brick( w/o mortar) = 0.00198 cum.
Thk.of mortar be 12mm.
vol.of brick with mortar = 242mm x 127mm x 87mm = 0.00267
cum.
No.of bricks in 1 cum. with mortar = 1/0.00267 = 373.99
Say = 374 bricks.
Cement Mortar required = 1-(374 x 0.00198) cum= 0.259 cum.
Say 0.26 cum
Add 15% for frog filling and wastage while execution.
Vol. of wet mortar = 0.299 cum.
Vol. of dry mortar (increase by 30%) = 0.388 cum.
For CM of 1:6
Qty. of cement = 1/7 x (1440 x 0.388) = 0.055 cum.
Qty. of sand = 0.055 x 6 = 0.330 cum

Answer / karan bagga

lets the take size of brick is .230*.115*.075. now calculate
the quantity for 10 cum.

Area of one brick without mortar -0.00198375 Cum
No of brick in 10 cum= 10/0.00198375 (Area of bricks).
=5041 nos of bricks.

now calc. the bricks quantity in 10 cum with mortar.

lets take the mortar used 10mm in brickwork then
size of brick will be taken with mortar is =.240*.125*.085=
0.00255 (Area of one brick with mortar).

now in 10 cum brickwork no of bricks calculated with mortar
is=10/0.00255 =3922 nos

calculate the mortar in cum= bricks without mortar- bricks
with mortar= 5041-3922=1119 nos
Now area of brick without mortar is .230*.115*.075*1119=2.22cum

now 15% for frog filling and wastage taken in acc.

=2.22+2.22*15/100=2.55 cum

Dry volume is the 1/3rd of wet volume of mortar=
2.55+2.55/1/3=3.40 cum.

now the ratio is 1:6=7

3.40*14%=.486 cum cement
3.40*86%= 2.92 Cum Sand

=.486/.0347= 14.01 bags/10 Cum
= 14.01*6=84.06 Bags/10 Cum

Answer / muthu kumaran

No of bricks = 500 [5(Stredger face with 10mm CM)*10(Header face with 10mm CM)*10(Header face with 10mm CM)]
Volume of mortar required = 1-500*0.19*0.09*0.09
= 0.2305 cubic metre
Cement required for 1:6 = (0.2305*1440)/7
= 47.41 Kg (Approx. 48 Kg)
(Density of cement 1440 Kg/cu.m)
Sand required = 284.5 Kg (Approx. 288 Kg)

Answer / sjtbehera

you are given 3”x4”x9” standard size of bricks
After placing mortar it became- 4”x5”x10” =
10.16cmx12.7cmx25.4cm
No of bricks are required=
10/.106x.127x.254=3069 nos
The size of brick without mortar= 3”x4”x9”=
7.62cmx10.1cmx22.8cm
Then net mortar required =10-(3069*.076*.101*.228)
= 4.62cum
Due to frog filling, brick bonding course and
wastage add 15%
Volume of wet mortar= 4.62+4.62x15%=5.30cum
When dry increase this qty. by 1/3rd=
5.30+5.30x1/3=7.06cum
Ratio is =1+6=7 cement = 7.06/7= 1.06 = 29 bags
Sand= 7.06*6= 42.36cum

What is ratio if m30

6 Answers   CCCL,

what is high type road and low type roads

0 Answers  

What are the advantages and disadvantages of lead products in construction?

0 Answers  

the internal dimensions of a ware house are 15m *5.6m and the maximum height of piles is 2.70m find the maximum numbers of bags to be storedin two piles

1 Answers  

Volume of 25kg putty bag & 40 kg putty bag volume??

0 Answers   NCCL,

how to calculate width and thickness of columns and beams for differnt area with example

1 Answers  

What will be the exam pattern and syllabus for j.e post of haryana staff selection commision? Advt no. (02/2015) Some people says it would only be objective type question papers while others say it would be same as ssc (1 objective,1 conventional) ?? Please answer this question it is needfull to all.

0 Answers   HSSC,

if dia of slab beam bar is38mm what its clear cover any method of provide clear cover

0 Answers   Omaxe,

Define Who designed the city of Washington DC?

0 Answers  

what is rebaring?

2 Answers   SSC,

hi, i am doing my B.tech third year and i want to have a job in Genpact...So can you help me which kind of job would be more appropriate for me in such a company and How should i prepare for an interview?

0 Answers   Genpact,

In the present situation of ban on mining sand from rivers,can we go for formation of earth dam filters viz;Horizantal sand blanket,inclined chimney and filters under rivetment with crushed rock sand of 6mm down size.If so what are the specifications and is there any codal provision for its authentication?

0 Answers