Answer / ramesh

I would like to answer by way of an example:

Generator capacity = 12MVA
Generator sub-transient impedance = 12%

With above two data,
the generator fault level can be calculated as folows:
Generator fault level = Generator capacity / generator sub-
transient impedance

Generator fault level = 12 MVA / 12% = 12MVA/.12 = 100MVA

To get fault current = Generator fault MVA / (1.732 *
generator rated voltage)

In case of single phase generator 1.732 to be ignored.

Answer / ramesh

The simplest formula is geno MVA / geno Xd".

Answer / ramesh

From your question I guess there is transformer between the
11kV & 6.6kV you are refering to. We need the transformer
MVA and the impedance percentage.
Once your provide the transformer MVA and its %impedance I
can answer further

Answer / shaan

Could u tell me what s mean by geno MVA/geno xd

Answer / dhiren patel

what is the refected current in 6.6 KV system in case of 11
kv side fault current is 40 KA and 8000 A full load current.

Answer / mnaoj sharma

Ramesh whats ur Email ID .I want to know more about you. I
mam electrical engineer . Your answers are absolutely right.

Answer / arun

Thanks Mr. Ramesh
from Arun Sharma
ENERGY AUDITOR

Answer / jignesh

we have 3 sets of generator running in parallel gen data 11kv 2000kva 1600kw transient reactance 0.1772and sub transient 0.1998 NGR 63.2 ohm . What is the fault level and fault current ? Please give me the solution on my mail id

Answer / vinod

RAMESH WTS UR EMAIL ID.....SEND ME UR EMAIL ID AT MY ID ...MY ID IS vinodmemoria07@gmail.com
i need ur help plz 4ward

Answer / ramesh

From your question I guess there is transformer between the
11kV & 6.6kV you are referring to. We need the transformer
MVA and the impedance percentage.
Once your provide the transformer MVA and its %impedance I
can answer further


mail-behera.ramesh@orisysinfotech.com

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