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What is the formula for finding fault level of generator?
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Answer / ramesh
I would like to answer by way of an example:
Generator capacity = 12MVA
Generator sub-transient impedance = 12%
With above two data,
the generator fault level can be calculated as folows:
Generator fault level = Generator capacity / generator sub-
transient impedance
Generator fault level = 12 MVA / 12% = 12MVA/.12 = 100MVA
To get fault current = Generator fault MVA / (1.732 *
generator rated voltage)
In case of single phase generator 1.732 to be ignored.
| Is This Answer Correct ? | 49 Yes | 4 No |
Answer / ramesh
From your question I guess there is transformer between the
11kV & 6.6kV you are refering to. We need the transformer
MVA and the impedance percentage.
Once your provide the transformer MVA and its %impedance I
can answer further
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / dhiren patel
what is the refected current in 6.6 KV system in case of 11
kv side fault current is 40 KA and 8000 A full load current.
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / mnaoj sharma
Ramesh whats ur Email ID .I want to know more about you. I
mam electrical engineer . Your answers are absolutely right.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / jignesh
we have 3 sets of generator running in parallel gen data 11kv 2000kva 1600kw transient reactance 0.1772and sub transient 0.1998 NGR 63.2 ohm . What is the fault level and fault current ? Please give me the solution on my mail id
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vinod
RAMESH WTS UR EMAIL ID.....SEND ME UR EMAIL ID AT MY ID ...MY ID IS vinodmemoria07@gmail.com
i need ur help plz 4ward
| Is This Answer Correct ? | 0 Yes | 1 No |
From your question I guess there is transformer between the
11kV & 6.6kV you are referring to. We need the transformer
MVA and the impedance percentage.
Once your provide the transformer MVA and its %impedance I
can answer further
mail-behera.ramesh@orisysinfotech.com
| Is This Answer Correct ? | 0 Yes | 1 No |
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