Answer / nagori salim

Vol of 1 bag of cement = 50/1440
= 0.0347 cumec

For 1 cumec = 1/0.0347
= 28.818
= 29 bags

Answer / kannan

28.8 bags

Answer / suresh ch

1 cum Cement = 1440 Kgs so 1440/50 = 28.8 bags

Answer / saravanakumar.a

cement voloume is for 1440kg/m3

1 bag 50 kg

=1440/50
=28.8 bags/cum

Answer / michael collins

Are you asking how many bags of cement in 1m3 of concrete or how many bags in one m3 of dry cement powder (i.e: a little more than a palette of portland).

concrete: roughly eight bags
drycement powder: roughly 30 bags.

Answer / yash tamakuwala

for m-20 mix concrete approx.. 8 bags needed

Answer / ahmed

Daer

the amount of cement in m3 according to ACI code with
mixture ratio 1:2:4 is 300 kg

and the amount of sand is 0.42 m3
and the amount of cource aggregate(gravel) is 0.84

regards

civil engineer
Ahmed Sami
IRAQ

Answer / mahammad dawood mandokhail

the volume of 1 cum cement bag is 0.034
so
1/0.034=29.41
or
one bag of cement is 50kg
so
50/0.034=1470
now
1470/50=29.41 that`s approximately equal to 30bags of cement.

Answer / a.k. max

if the portland cement density is 1505kg/cu.m. then in 1
cu.m. we will have 1505kg of cement. as a result in 1cu.m.
we have 1505/50=30.1 bags

Answer / m.shilpa

Density of cement is 1440kg/cum.
weight of 1 cement bag is 50kgs.
By dividing density by weigt of bag we can get number of
bags per cum.
Thatis 1440/50 = 28.8 bags.
we can do it in other form to.

1bag is equal to 35 litres of water
therefore 1cum =1000litres
total no of bags = 1000/35 =28.8 bags

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