Answer / kang chuen tat (malaysia - pen

(a) Theoretical oxygen gas = 100 kmol C (1/1) = 100 kmol of oxygen gas. (b) Theoretical air = (100 kmol) (1 / 0.21) = 476.2 kmol. (c) Amount of air required 50 % excess = 476.2 kmol (1.5) = 714.3 kmol. (d) Carbon consumption to produce carbon dioxide gas = 0.8 x 100 = 80 kmol = oxygen consumption to produce carbon dioxide gas. Carbon consumption to produce carbon monoxide gas = 0.2 x 100 = 20 kmol = 2 times oxygen consumption to produce carbon monoxide gas, then oxygen consumption to produce carbon monoxide gas = 20 / 2 = 10 kmol. Total oxygen gas required = 80 + 10 = 90 kmol. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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In a furnace, 2 chemical reactions are happening – 1 mole of solid carbon reacts with 1 mole of oxygen gas to generate 1 mole of carbon dioxide gas; 1 mole of solid carbon reacts with 0.5 mole of oxygen gas to generate 1 mole of carbon monoxide gas. In a given process, 100 kmol of carbon is burned in a furnace. (a) Calculate the theoretical oxygen gas needed by assuming that all the carbon is burned completely to carbon dioxide gas. (b) Calculate the theoretical air needed by assuming that all the carbon is burned completely to carbon dioxide gas and there is only 21 % of oxygen gas. (c) Determine the amount of air required (in kmol) if 50 % excess oxygen gas must be satisfied for (a) and (b). (d) It has latter been found that 20 % of the carbon undergoes incomplete combustion resulting to carbon monoxide gas production. The rest of the carbon undergoes complete combustion. Calculate the total oxygen gas required stoichiometrically based on the actual process.

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