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Have you studied pipelining? List the 5 stages of a 5 stage
pipeline. Assuming 1 clock per stage, what is the latency of
an instruction in a 5 stage machine? What is the throughput
of this machine ?

Answers were Sorted based on User's Feedback



Have you studied pipelining? List the 5 stages of a 5 stage pipeline. Assuming 1 clock per stage, w..

Answer / mallikarjun patil

I have worked on design consit of 5 stage pipeline
processor.

With 5 stage pipeline it takes minimum 5 clock cycle to to
execute a instuction. So latency of instuction is5 clock
cycles.

Through put is one instruction per clock cycle + initial
overhed of 4 clock cycle

Is This Answer Correct ?    27 Yes 3 No

Have you studied pipelining? List the 5 stages of a 5 stage pipeline. Assuming 1 clock per stage, w..

Answer / 12345678

1.Instruction fetch
2.decode instruction and read register files
3.execute
4.data to access from memory
5.write back

throughput is the total amount of work done in a given time,

Is This Answer Correct ?    21 Yes 9 No

Have you studied pipelining? List the 5 stages of a 5 stage pipeline. Assuming 1 clock per stage, w..

Answer / kiran chowdary

Throughput is 1 instruction/clock cycle. It is a dumb answer to say the latency as 5 cycles. It is pipelined architecture. Only during initial time it takes 5 cycles to fetch and all that. Later on all executions are pipelined so it takes only 1 cycle to execute one instruction unless there is any blocking activity like memory write back etc.

Is This Answer Correct ?    6 Yes 8 No

Have you studied pipelining? List the 5 stages of a 5 stage pipeline. Assuming 1 clock per stage, w..

Answer / manju

the steps are same as mentioned in the above thread jus
putting these in proper order.
1.Instruction fetch
2.decode instruction and read register files
3.data to access from memory
4.execute
5.write back

please correct if it is wrong.

Is This Answer Correct ?    1 Yes 12 No

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Need to convert this VHDL code into VLSI verilog code? LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.ALL; ----using all functions of specific package--- ENTITY tollbooth2 IS PORT (Clock,car_s,RE : IN STD_LOGIC; coin_s : IN STD_LOGIC_VECTOR(1 DOWNTO 0); r_light,g_light,alarm : OUT STD_LOGIC); END tollbooth2; ARCHITECTURE Behav OF tollbooth2 IS TYPE state_type IS (NO_CAR,GOTZERO,GOTFIV,GOTTEN,GOTFIF,GOTTWEN,CAR_PAID,CHEATE D); ------GOTZERO = PAID $0.00--------- ------GOTFIV = PAID $0.05---------- ------GOTTEN = PAID $0.10---------- ------GOTFIF = PAID $0.15---------- ------GOTTWEN = PAID $0.20--------- SIGNAL present_state,next_state : state_type; BEGIN -----Next state is identified using present state,car & coin sensors------ PROCESS(present_state,car_s,coin_s) BEGIN CASE present_state IS WHEN NO_CAR => IF (car_s = '1') THEN next_state <= GOTZERO; ELSE next_state <= NO_CAR; END IF; WHEN GOTZERO => IF (car_s ='0') THEN next_state <= CHEATED; ELSIF (coin_s = "00") THEN next_state <= GOTZERO; ELSIF (coin_s = "01") THEN next_state <= GOTFIV; ELSIF (coin_s ="10") THEN next_state <= GOTTEN; END IF; WHEN GOTFIV=> IF (car_s ='0') THEN next_state <= CHEATED; ELSIF (coin_s = "00") THEN next_state <= GOTFIV; ELSIF (coin_s = "01") THEN next_state <= GOTTEN; ELSIF (coin_s <= "10") THEN next_state <= GOTFIV; END IF; WHEN GOTTEN => IF (car_s ='0') THEN next_state <= CHEATED; ELSIF (coin_s ="00") THEN next_state <= GOTTEN; ELSIF (coin_s="01") THEN next_state <= GOTFIV; ELSIF (coin_s="10") THEN next_state <= GOTTWEN; END IF; WHEN GOTFIF => IF (car_s ='0') THEN next_state <= CHEATED; ELSIF (coin_s = "00") THEN next_state <= GOTFIF; ELSIF (coin_s ="01") THEN next_state <= GOTTWEN; ELSIF (coin_s = "10") THEN next_state <= GOTTWEN; END IF; WHEN GOTTWEN => next_state <= CAR_PAID; WHEN CAR_PAID => IF (car_s = '0') THEN next_state <= NO_CAR; ELSE next_state<= CAR_PAID; END IF; WHEN CHEATED => IF (car_s = '1') THEN next_state <= GOTZERO; ELSE next_state <= CHEATED; END IF; END CASE; END PROCESS;-----End of Process 1 -------PROCESS 2 for STATE REGISTER CLOCKING-------- PROCESS(Clock,RE) BEGIN IF RE = '1' THEN present_state <= GOTZERO; ----When the clock changes from low to high,the state of the system ----stored in next_state becomes the present state----- ELSIF Clock'EVENT AND Clock ='1' THEN present_state <= next_state; END IF; END PROCESS;-----End of Process 2------- --------------------------------------------------------- -----Conditional signal assignment statements---------- r_light <= '0' WHEN present_state = CAR_PAID ELSE '1'; g_light <= '1' WHEN present_state = CAR_PAID ELSE '0'; alarm <= '1' WHEN present_state = CHEATED ELSE '0'; END Behav;

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