how to calculate no. of cement bags consumed in 1:4 and 1:6
proportion RR Masonary and the quantity of sand also
Answers were Sorted based on User's Feedback
Answer / nisikanta
First of all calculate total volume of RR masonry.Then add
33% of volume more than actual volume of wet material.then
for 1:4 ;1 cement:4 coarse sand.Total volume/5=Vol of cement.
no of bags of cement=Vol of cement/.035.For 1:6 just put 6
in place of 4.
Is This Answer Correct ? | 23 Yes | 24 No |
Answer / sudhir pawar
Part A : The data :
Cement: 330/bag
Rubble : 2562/brass
Labour :2200/brass
Sand 6500/ brass
You already know that : I brass = 100 Cft
Desired Profit 25%
Specifications :
Rubble masonry Width 18″ to 36"
for wall compound ht upto 3′ from ground level
in cement mortar in ratio : ( 1:5 )
Material for 1 cum:
Cement : 330*(0.45*1.57*28.8)/6= Rs.1119
Sand: 6500*0.3529*5*(0.45*1.57)/6= Rs.1350.50
Rubble: 2562*0.3529*1.45 = Rs.1311
Labour : 2200*0.3529= Rs.776
Total: Rs.3756 RS. 4556.50
Profit:Add@ 25%: Rs. 1139.13
Total: Rs. 5695.63 Rs/cum.
Is This Answer Correct ? | 2 Yes | 6 No |
Answer / j.edison
cement mortar1;4 1440divided by4=360kg
cement mortar 1;6 1440divided by 6=240kg
Is This Answer Correct ? | 17 Yes | 24 No |
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