What is the power ratio between power in Star and Delta
circuit?
Answers were Sorted based on User's Feedback
Answer / karthick
in star connection
line voltage is=(3)^(1/2)*phasevoltage
line current is=phase current
in delta connection
line voltage is =phase voltage
line current is =(3)^(1/2)*phase current
power ratio=( ((3)^(1/2)*phasevoltage*phase current)/((((3)^
(1/2)*phasevoltage*phase current))
so power ratio is =1.
Is This Answer Correct ? | 62 Yes | 36 No |
Answer / ganeshagraja samanta
the ratio of power in star & delta is 1:3
Is This Answer Correct ? | 35 Yes | 10 No |
Answer / jothi mahalingam
power ratio b/w star and delta is 1/3.In star, total power
will be 1/3 times of delta total power.
Is This Answer Correct ? | 20 Yes | 10 No |
Answer / karl
If placing 3 resistors in Delta rather than Star will end
up with 3 times more heating power. This is because you
have sq root of 3 times more voltage across each resistor
in Delta and hence end up with the sq root of 3 times more
current through each resistor. The sq root of 3 of more
voltage times the sq root of 3 of more current than, star
connected resistors means 3 times more power. Capacitor
are often connected in Delta for power factor correction as
this offers 3 times more reactive power than in Star
connection, though be aware they need to be able to cope
with line voltage across each Cap in Delta.
Is This Answer Correct ? | 10 Yes | 4 No |
Answer / alpesh surat
i think transformer just step up or step down voltage or
current only but power remains same(constant).so ratio of
p1 to p2 is 1 when same transformer connected in star or
delta.
Is This Answer Correct ? | 13 Yes | 11 No |
Answer / reshi
The power transformation ratio in the transformer is
1:1.Only the voltage and currents are subjected to
change.Pri MVA=Secondary MVA. Except to compensate for some
losses.
Is This Answer Correct ? | 12 Yes | 11 No |
Answer / pratik chhatbar
If placing 3 resistors in Delta rather than Star will end
up with 3 times more heating power. This is because you
have sq root of 3 times more voltage across each resistor
in Delta and hence end up with the sq root of 3 times more
current through each resistor. The sq root of 3 of more
voltage times the sq root of 3 of more current than, star
connected resistors means 3 times more power. Capacitor
are often connected in Delta for power factor correction as
this offers 3 times more reactive power than in Star
connection, though be aware they need to be able to cope
with line voltage across each Cap in Delta.
Thanks
Is This Answer Correct ? | 7 Yes | 6 No |
The power is depends on the resistance of the winding. Lets
Take "R"ohm resistance of winding and connect in star
configuration.
then transform it to delta. You will see the result. It
will "R/3". So low resistance, high current, power.
Is This Answer Correct ? | 0 Yes | 0 No |
power = 3vicos
in delta Iphase = Iline/rt3.
Vphase = Vline
ie in delta connected ckt P= rt3VphaseIphasecos
IIly in star connected vphase=Vline/rt3,
Iline=Iphase
ie Power = rt3 vpahseIphaseCos
ie. in both star and delta power remain same
therefore the Power ratio = 1.
Is This Answer Correct ? | 25 Yes | 26 No |
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