Answer / arulkumaran

KW = KVA*PF
KW = 1600*0.9
KW = 1440
11KV PRIMARY CURRENT=
KW = 1.732*KV*I*PF root(3) = 1.732
1440 = 1.732*11*I*0.9
1440/1.732*11*0.9 = I
I = 83.98 AMPERE
415V SECONDRY CURRENT=
WATTS = 1.732*V*I*PF
1440000 = 1.732*415*I*0.9
I = 2226 AMPERE

Answer / manimaranmuthu.m

11KV PRIMARY CURRENT[HT]:


KW = KVA*PF


POWER [KW]= 1600*0.9

POWER = 1440 KW

POWER [KW]=√3*KV*I*PF
root(3) = 1.732

1440 = 1.732*11*I*0.9

1440/1.732*11*0.9 = I

I = 83.98 AMPERE

415V SECONDRY CURRENT[LT]:

WATTS = 1.732*V*I*PF

1440*1000 = 1.732*415*I*0.9

I = 2226 AMPERE

Answer / suhailpro

Primary side voltage be 11KV,
Transformer's capacity= 1000KVA

Real power= Apparent*Power factor
KW=KVA*Power factor
if Power factor = 0.95
Power= 1000*0.95
Power=950KW
We also know,
Power(KW)=(root 3)*(KV)*I*Power factor
950=1.732*11*0.95*I
I(Current)= 49.7A

Secondary Voltage Be 433V
We know that,
Power(watts)=(root 3)*V*I*Power factor
Power=950KW=950000W
950000=1.732*433*I*0.95
I= 1333.4 A

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