calculation of cement bags in 1:2:4 concrete mix
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Answer / basharat ali
1.54/sum of ratio
1.54/7=.22cum cement
.22/.0347=6.340bags cement (Say 7)
.22×2=.44cum :-15.5368cft :-19.047bags
.22×4=.88cum:- 31.07cft:-38.09bags
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Answer / engr. daniel otoyo
Normal concrete such as 1:2:4 mix has a density of 2400kg/cm
1cm of concrete will weigh 2400x1kg = 2400kg
Sum of mix ratio = 1+2+4 = 7
Ratio (fraction) of cement weight = 1/7
Weight of cement (in 1cm concrete) is therefore = 1/7 x 2400 = 342.857kg
Cement in 50kg bags will give us 342.857/50 = 6.86kg
This approximates to 7bag/cm of 1:2:4 concrete if the desired strength is to be achieved.
Other constituent like fine and coarse aggregates can be solved likewise and their densities used to translate their weight into volumes.
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Answer / ruatsanga
For 1 m3 of Concrete (1:2:4)
Required volume of concrete = 1 m3
Estimated volume of dry material = 1 x 1.54 (1.54 = constant)
= 1.54 m3
Mix total = 1 + 2 + 4 = 7 ( 1 : 2 : 4 )
Ingredients Volume = 1.54 x 1/7
= 0.22 m3 of cement
#Bags of cement = 0.22 / 0.035 (per 50 kg Bag)
= 6.289 bags of cement
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Answer / gopalakrishna
cement: 1*1.33/7=0.19*1440=273.6/50=5.47bags say 6
sand :2*1.33/7=0.38 cum ,jelly 20mm =4*1.33/7=0.76cum
Is This Answer Correct ? | 8 Yes | 10 No |
Answer / ngozi favour
no volume is given. Then it
just 1bag of cement to 100kg
of fine aggregate and 200kg
of coarse aggregate
Is This Answer Correct ? | 7 Yes | 12 No |
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