how to calculate sand, cement quantity for plastering (1:5)? what"s the formula?
Answers were Sorted based on User's Feedback
Answer / rajarshi basu
Let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.
Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]
Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3
Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,
1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)
2)Sand required= [1.92 x (5/6)]= 1.60 cu. m
[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.
One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]
Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
Is This Answer Correct ? | 269 Yes | 26 No |
Answer / sandeep tv
let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.
Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]
Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3
Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,
1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)
2)Sand required= [1.92 x (5/6)]= 1.60 cu. m
[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.
One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]
Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
Is This Answer Correct ? | 58 Yes | 12 No |
Answer / ashwin
cement:sand= 1:5
for 1cum= 1/6
=0.166
so cement for 1 cum=0.166cum
but volume of 1 cement bag is=.033cum
bag required per cum is=.166/.033
=5 bags
sand required is=0.166*5
=0.833 cum
Is This Answer Correct ? | 100 Yes | 57 No |
Answer / yogesh khandelwal
Let Area to be plastered=100 m^2
& Thickness of plaster= 12mm=(12/1000)m= 0.012m
Volume of mortar required= 100 x 0.012= 1.20 m^3
Add 20% extra mortar for filling joint,depressions and
wastage.
Volume of the mortar= [0.20 X 1.20]+ 1.20=1.44 m^3
[Wet Volume]
Increase further by One-third of the volume to get Dry
volume
Quantity becomes= [(1/3) X 1.44]+ 1.44=1.92 m^3
Summation of proportion=1+5=6
For 12mm plastering in 1:5 cement:sand mortar mix,
1)Cement required= 1.92/6= 0.32 cu. m
No. of bags of cement= 0.320/0.0347=9.22 bags
>>9 bags(say)
Kgs of cement required=9 x 50= 450 kg (approx)
2)Sand required= [1.92 x (5/6)]= 1.60 cu. m
[Weight of 1 bag of cement= 50 kg
Cement should be always measured by weight to avoid
variation.
One 50 kg bag of cement weighs 1440 kg/cu. m
Volume of 1 bag of cement= 50/1440=0.0347 cu. m ]
Therefore to convert Cu. m into No of bags of 50 kg
cement,just divide the volume of cement by 0.0347
Is This Answer Correct ? | 13 Yes | 4 No |
why should we have to take 20% of wet mortar & 1/3rd of Dry mortar......is there eny code for that...or plz tell me where it coms from......plz clear me ....
Is This Answer Correct ? | 12 Yes | 3 No |
Answer / adz
1:5 proportion for (1)cement @ 40kg): (5)sand @ 33 kg(S.G
@2.6) gives you approximate volume of 0.142 cubic meter.
if you want exact volume, provide the specific gravity of
your materials and include air content and water for your
volume...
Is This Answer Correct ? | 8 Yes | 0 No |
Answer / abrar
c:m ratio for plastering (1:5) for 1 cum
sand 1cum = 1.25cum .... constant in all ratios
cement 1cum = 1.25 x 1440
------------ = 360 kgs = 7.2 bags
5
Is This Answer Correct ? | 16 Yes | 12 No |
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