The job profile as a Service Engineer?

0 Answers  

---

Explain what are the assumptions made on conservation equation?

0 Answers  

---

Explain the procedure to estimate the friction factor involved in heat exchanger tubes?

0 Answers  

---

Are some heat transfer services more prone to tube vibration that others for a shell and tube exchanger?

0 Answers  

---

How can I treat a waste stream containing both hexavalent chromium and arsenic?

0 Answers  

---

---

What is Vacuum? If pressure is less than that of atmospheric, can we call it vacuum? If so some places have less atmospheric pressures, can we call people living there are living in vacuum?

5 Answers   ISRO, TCS,

---

Plz if anybody has placement paper of HAL mail me i m Chemical engg my id er.kotnala@gmail.com

0 Answers   HAL, IOCL,

---

how to convert Nm3/hr to Kg/hr for air, @ 10.4 kg/cm2.g dischare pressure, does density doesn't affect on calculation?

1 Answers  

---

how should i prepare for my placements.i am a student of chemical eng,final year,thapar university

0 Answers   IOCL,

---

ENGINEERING MATERIAL - EXAMPLE 12.1 : In crystal material, hexagonal crystal system could form 4-digit index in certain direction of solid. For [1(-1)0] direction in the hexagonal crystal systems of particular catalyst applied in fume removal of incinerator, what is the four-digit index for this direction? Hint : The transformation equations between the 3-digit [h'k'l'] and the 4-digit [hkil] indices are : h = (1/3) (2h'-k'); i = - (h + k); k = (1/3) (2k'-h'); l = l' A. [(-1)100] B. [1(-1)00] C. [(-1)000] D. [00(-1)(-1)] E. [(-1)0(-1)0]

1 Answers  

---

What factors go into designing the vapor space of kettle type reboiler?

0 Answers  

---

Water flows through a pipe with circular cross sectional area at the rate of V / t = 80 L / s where V is the volume and t is time. Let Av = 80 L / s where A is cross sectional area and v is velocity of fluid. For point 1, the radius of the pipe is 16 cm. For point 2, the radius of the pipe is 8 cm. Find (a) the velocity at point 1; (b) the velocity at point 2; (c) the pressure at point 2 by using Bernoulli’s equation where P Rgy 0.5 RV = constant. P is the pressure, R = density of fluid, V = square of fluid’s velocity, g = gravitational constant of 9.81 N / kg and y = 2 m = difference of height at 2 points. The pressure of point 1 is 180 kPa.

1 Answers  

---