Answer / kang chuen tat (malaysia - pen

Answer 51 - (a) Cb = (1000 g / L) / (18 g / mol) = 55.556 mol / L. (b) X = 1 - 1 / exp [ kt (Cb) ] = 1 - 1 / exp (0.00083 x 45 x 55.556) = 0.8744. (c) X = 1 - 1 / exp [ kt (Cb) ], 1 / exp [ kt (Cb) ] = 1 - X, exp [ kt (Cb) ] = 1 / (1 - X), (Cb) kt = ln [ 1 / (1 - X) ], t = 1 / [ k (Cb) ] ln [ 1 / (1 - X) ] = ln [ 1 / (1 - X) ] / [ k (Cb) ]. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

CHEMICAL ENERGY BALANCE - EXAMPLE 11.4 : Calculate the bubble temperature T at P = 85-kPa for a binary liquid with x(1) = 0.4. The liquid solution is ideal. The saturation pressures are Psat(1) = exp [ 14.3 - 2945 / (T + 224) ], Psat(2) = exp [ 14.2 - 2943 / (T + 209) ] where T is in degree Celsius. Please take note that x(1) + x(2) = 1. Please take note that y(1) + y(2) = 1, y(1) = [ x(1) * Psat(1) ] / P, y(2) = [ x(2) * Psat(2) ] / P, * is multiplication. P is in kPa.

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i'm a chemical engineer with an aggregate of 80% and i'm going to attend for TCS next week...if i encounter a question like this how i have to answer... WHY YOU CHOOSE SOFTWARE RATHER THAN YOUR CORE COMPANIES?

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THERMODYNAMIC - EXAMPLE 10.2 : A cylinder with a movable piston contains 0.1 mole of a monoatomic ideal gas. The piston moves through state a, b and c. The heat Q, changes from state c to a is + 685 J. The work W, changes from state c to a is - 120 J. The work, W performed from state a to b then to c is 75 J. By using the first law of thermodynamic, U = Q + W where U is the internal energy : (a) Determine the change in internal energy between states a and c. (b) Is heat added or removed from the gas when the gas is taken along the path abc? (c) Calculate the heat added or removed when the gas is taken along the path abc?

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