Answer / guest

if it is 3 phase
KVA=1.732*V*A
1000=1.732*440*A
A=1.31A

for 1 phase
KVA=V*A
1000=440*A
A=2.27A

Answer / niti

If consider Is in three phase circuit

A=kva*1000/v*1.732

therefore
=1*1000/440*1.732
=1.31A

If Consider is in Single phase circuit
A=1*1000/V
=1*1000*/440
=2.27A

Answer / golak bihari naik

2.27A

Answer / fazal

Amps = KVA/1.732*V*p.f

= 1*1000/(1.732*440*0.8)
=1.640 Amps

Answer / pearl ganesh

kva=1.732*v*I

I=kva*1000/1.732*440
I=1*1000/1.732*440
I=1.31 Amps

Answer / ameerlal

KVA(Apperent Power)=1.732 * Line voltage * line Current(It
is in Three Phase System)
According to above formula
I= KVA/1.732*Line Voltage
I=1000/1.732*440
I=1.312Amp.

Answer / golak bihari naik

For 3-Ph system
KVA(Apparent Power)=1.732*V*I
I=(KVA/1.732*V)*1000
I=(1/1.732*440)*1000
=1.31 A

For a 1-Ph system

KVA=V*I
I=(1/440)*1000
=2.27 A

Answer / anil

when kva given PF not to consider because formula to find
current is


1)When KVA know
L.Current= KVAX1000/L.VoltsX1.732

2)when kw knows
L.Current= KWx 1000 /L.VoltsX1.732XPF

3)when HP knows
L.Current= HPx746/L.VoltsX1.732XPFxefficeincy


PF effects kw , that is reason our power unit measuring is
kwh

Answer / subbu

1.39Amps

Answer / manikandan

\

1kva=1000/1.732*440=1.32A for 3 phase


1kva=1000/240=4.16A for single phase

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