Answer / raeworx

SINGLE PHASE CIRCUIT three phase circuit

V(PHASE)= V(LINE)/1.732 KVA = I*V*PF*1.732
= 254V I = KVA/V*PF*1.732
THEREFORE I = KVA/V = 1000/(440*.8*1.732)
= 1000/254 = 1000/ 609.7
= 3.94A = 1.64A

Answer / sushant

KVA = (1.73*VICOS PHI)/1000
1 = (1.73*440*I*0.8) / 1000
I=1000/(1.73*440*0.8)
= 1000/608.96
I = 1.64 A

There is no ralation between volt,ampere & freq

Answer / deepak

KVA(Apperent Power)=1.732 * Line voltage * line Current(It
is in Three Phase System)
According to above formula
I= KVA/1.732*Line Voltage
I=1000/1.732*440
I=1.312Amp.


Is This Answer Correct ? 7 Yes 4 No

0
Ameerlal

Re: how many amps in 1 KVA? V=440v, PF=0.8 and FREQ=50Hz
Answer
# 13

kva=1.732*v*i*cos

i=kva/1.732x440x0.8

i=1.6A

Answer / deepak g shinde.

When Kva known I = Kva*1000/V*1.732
I=kva*1000/1.732*440
I=1*1000/1.732*440
I=1.31 Amps
I consider this only for three phase & not for single
phase ,because there is very rare chance of 440v in single
phase.

Answer / praveen

1.64

Answer / pearl ganesh

kva=1.732*v*I*p.f

I=kva*1000/1.732*440*0.8
I=1*1000/1.732*440*0.8
I=1.640 Amps

Answer / suresh m s

kva=1.732*v*i*cos

i=kva/1.732x440x0.8

i=1.6A

Answer / amit.sonmale

Amp=KVA /P.F
=1/0.8
=1.25Amps.

Answer / pradeep baliyan

I KW = V * A * 1.732 * .8 / 1000
(For 3 Phase)
Kva = V*A*1.732/1000 (3 phase, V= 415)

Kva =V*A/1000 (1 Phase, V= 220)

Answer / kumar

1.25Amps

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