QUANTUM COMPUTING - EXAMPLE 32.10 : In quantum computing, the conversion of Control Not (CNOT) gate in two input quantum bit gate could be decribed as : | 00 > --> | 00 >, | 01 > --> | 01 >, | 10 > --> | 11 >, | 11 > --> | 10 >. If | P > = 0.707 ( | 01 > - | 11 > ), find the value of CNOT | P >.
QUANTUM COMPUTING - ANSWER 32.10 : Since | 01 > --> | 01 > and | 11 > --> | 10 >, then CNOT | P > = CNOT [ 0.707 ( | 01 > - | 11 > ) ] = 0.707 ( | 01 > - | 10 > ). The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.28 : In the development of a small engineering facility for biochemical processing, completed contract method is applied in its construction accounting. In a short contract period, let the (contract price) = A. Let the (costs to date) = B; (estimated cost to complete) = C. (a) Find the values of : (i) estimated total costs; (ii) total estimated profit; (iii) percent completion to date. (b) If the project contract is 100 % completed : (i) find the total gross profit recognized; (ii) what is the exact numerical value of C?
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Question 52 - The half-life for first order reaction could be described in the differential equation dC / dt = -kC where k is a constant, C is concentration and t is time. (a) Find the equation of C as a function of t. (b) Find the half life for such reaction or the time required to reduce 50 % of the initial concentration, where k = 0.139 per minute. (c) When the initial concentration Co is 16 mol / cubic metre, how long does the reaction required to achieve the final concentration of 1 mol / cubic metre?