Answer / carl_ellis

Answer: 239.2 mmH2O

Present max flow rate = 1700 nm3/hr
Present max DP (at max flow rate) = 120 mm H2O

New max flow rate = 2400 nm3/hr
New max DP (at new max flow rate) = x

2400/1700 = 1.412 or an increase of 141.2% in flow rate.

The DP and the flow rate relationship is a square root relationship, but the calculation is based on normalized percentage.

X = 1.412^2*120
X = 1.993*120
X = 239.2 mmH2O

The increase in max DP from 120 to 239.2 mmH2O is an increase of
239.2/120 = 1.993 or 199.3% increase in max DP at max flow rate.

Sq root of 1.993 = 1.412 or 141.2% increase in max flow rate (2400/1700)

Carl Ellis
Measure First

Answer / alim

I think the equation is not straight forward, you need some repetition formula for calculating this.

Normally, I will use some software to do this kind of calculation such as InstruCalc. The data that you presented in the question is not enough. I am assuming that you are using the orifice in as the flow element, then you still need viscosity and specific gravity of the fluid.

please help me to get the below mentioned quires,which i have to submit for my client.[INSPECTION TEST PLAN] 1]I.T.P for Calibration of all instrument. 2]I.T.P for SS tubing. 3]I.T.P for Fire & Gas devices. 4]I.T.P for CCTV & telecommunication. 5] I.T.P for loop checking.

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