we have LPG spherical Tank and we want to install DP Xmtr
for level measurement.below are the physical measurements
Total height of tank is 1850 mtr but 0% level is 1000mm
above bottom and 100% level is 450 below upper side.What is
the LRV and URV and please mention the formula .The SG of
LPG is 0.53 and Wet Leg method will be used.
Answers were Sorted based on User's Feedback
Answer / bill arbour
If the height of this spherical tank is 1850 meters, then
it has got to be the biggest spherical tank in the world.
It would be almost 2 Kms high. Check your numbers.
Is This Answer Correct ? | 8 Yes | 1 No |
Answer / jabi
suppose the total height of tank is 18.5 mtr
LRV= 1mtr above from ground
URV= 14 mtr above from the ground(4.5mt below the top heigt)
Low pressure side total height= 13mtr
Differential pressure at LRV:
P(high)= height x SG
= 1 mtr x 0.53
= 530 mmWC
P (low)= 13 mtr x 0.53
= 6890 mmWC
LRV is equal to P(high)-P(low)
= 530-6890
= -6360 mmWC
Differential Pressure at URV:
P(high)= 14mtr x 0.53
= 7420 mmWC
P(low)= 13 mtr x 0.53
= 6890 mmWC
URV is equal to P(high)-P(low)
= 7420-6890
= 530 mmWC
Is This Answer Correct ? | 4 Yes | 0 No |
Answer / ghalib
first the question is not clear,the total height of the
tank given in mtr(1850)but the 0% is above 1000mm,ok,but
100% level is 450 below upper side,(this 450 is in what-mm
or meter,pls make it clear
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / chinna babu
LRV=(1m * 0.53) -(18.5 m *0.53)
URV= (14 m * 0.53)- (18.5 m *0.53)
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / nestor
let us consider at 100% 450meters upper side so the wet leg measures:
1850 - (450 meter + 1 meter) = 1399 meter
so height(specific gravity) = 1399 (0.53) = 741.47 meter
span = URV-LRV
LRV = 1 meter(0.53) = 0.53 meter
so URV = span+LRV = 741.47 + 0.53 = 742 meter
Is This Answer Correct ? | 0 Yes | 3 No |
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