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A temperature sensor (RTD) connected via a temperature transmitter is adjusted to give an output of 4ma at 60 deg and 20 ma at 600 deg.
This output (4-20ma) from the transmitter is connected to an IGBT-inverter to control a high speed (-12,000 to +12,000 RPM) DC motor.
And in the inverter it is programmed as, for 4ma the motor speed will be -3,000 RPM and for 20ma the motor speed will be +10,000 RPM.
The question is : If the motor speed is +5,500 (RPM), what will be the temperature?
(-sign indicates that the motion is in reverse direction).
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Answer / ravi
mr ghulam mohammed can you plz give me full details for your
calculation.i mean the formulas.
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Answer / srikanth
At -3000 rpm temp=60 ma=4
At 0 rpm temp=60+124.6=184.6 ma=9.46
At 5500 rpm temp= 60+353=413
ma=14.45
At 10000 rpm temp=60+540=600
ma=20
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Temperature is 492 deg.;ma output= 14.46
| Is This Answer Correct ? | 0 Yes | 1 No |
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