what is procedure to find the volume of material in M20
concrete?
Answers were Sorted based on User's Feedback
Answer / ajithprasa vd
M20 means 1 part cement , 1.5 part sand and 3 part aggregate
Cement 7.5 bag
Sand 0.5 M3
Aggregate o.85 M3
| Is This Answer Correct ? | 8 Yes | 1 No |
Answer / engineer harry mrar
403kg cement
.42cum sand
.84 aggregate
181 liter water
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / ashok sakhare
M20 ratio is 1:1.5:3
(i)Total motor wet = 1+1.5+3= 5.5
(a) Volume of aggregate = 35.5*1.57= 0.856m3 Dry motor/ Cum
(b) volume of sand =1.5/5.5*1.57= 0.3
428m3/ Cum ( Dry motor)
(c) volume of cement =1/5.5*1.57 =( Dry cement) 0.285m3*1440=399 kg.
399/50kg= 7.99bags/Cum
(note: 1.57 for 1m3 Dry motor)
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / muzammil ahmed
m20=1:1.5:3=5.5, dry mix for im3 is 1.57
1.57/5.5=0.285x30 = 8.5bags OR
=0.285x1500=428.18kg/50=8.55bags(cement)
=0.285x1.5 =0.427x35.28=15cft
=0.285x3 =0.855x35.28=31cft
| Is This Answer Correct ? | 0 Yes | 3 No |
Answer / i.rajamohamed. p.s.y.e.college
M20 ratio is 1:1.5:3( TAKE 20mm aggregate)
(i)add ratio= 1+1.5+3= 5.5
(a) volume of aggregate = 1\7*1.57 = 0.22m3
(b) volume of sand =1.5/7*1.57= 0.33m3
(c) volume of cement =3/7*1.57 = 0.67m3*1440=964 kg.
(note: 1.57 for 1m3 box)
| Is This Answer Correct ? | 5 Yes | 16 No |
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11 Answers L&T, Sobha Developers,
As per thumb rule cement required per 1 cum of M20 concrete is 411Kg/cum(1.57/5.5=0.285cum of cement i.e 0.285*1440=411Kg).But as per PWD rate analysis cement required is 347Kg/cum.the difference is 64Kg.This kind of difference is coming every grade of concrete.Can you give perfect suggestion regarding this.
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