Answer / gees

325 volts ( with no load applied ).This is because the
capacitor, normally on the output charges up to the PEAK
vale of the waveform ( 1.414 times the RMS value of 230V )

Answer / rajesh tewari

it is depending upon firing angle of thyristor. how many we
requres in output.we make the thysistor as we need.

Answer / shoebullah

0.7 volts will be the voltage
drop per diode ... If your
applying a.c only to bridge
without using any other
element like capacitor and
inductance then it should be
0.7*4=2.8,so the answdr is
228.2 volts will be the output

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