how to write the program for single push button by using
ladder diagram
Answers were Sorted based on User's Feedback
Answer / rajesh rajan
I am also faced same situation and i made a logic like this
[ ]
[----[ ]---i---[\]-------------( )--]
[ PB i M2 O/P ]
[ i ]
[----( )---i ]
[ O\P ]
[ ]
[----( )---[\]-i-[\]-----------( )--]
[ O\P PB i M2 M1 ]
[ i ]
[----[ ]-------i ]
[ M1 ]
[ ]
[ ]
[----[ ]---i---[ ]-------------( )--]
[ M1 i PB M2 ]
[ i ]
[----[ ]---i ]
[ M2 ]
[ ]
Is This Answer Correct ? | 48 Yes | 9 No |
Answer / naresh yadav
[---II---------------(p)-----]
i0.0 a0.0
[-i--II-----I\I--i------()---]
i a0.0 o0.0 i o0.0
i i
i--II-----I\I--i
o0.0 a0.0
II - Normally Open
I\I - Normall Closed
() - Output
(p) - pulse
Is This Answer Correct ? | 26 Yes | 21 No |
Answer / sauri
PB
|------II-----(osr)------<b3:0/0>---|
| |
| b3:0/0 M2 |
|-----II------I/I--------<M2>-------|
| b3:0/0 M2 |
|-----I/I-----II----|
b3:0/0=binary bit;
PB=push button;
osr=one shot rising;
II=NO push button;
I/I=NC push button;
M2=motor for start and stop;
for any query pls contact:-
sauriprasad@gmail.com,
santosh33cooldude@gmail.com,
rkskumarpanda@gmail.com
Is This Answer Correct ? | 4 Yes | 3 No |
Answer / sara
Sorry for my mistake in the third network
|---| |---------|/|--------(M0.0)-----|
I0.0 i M0.1
i
---| |---
M0.0
|---| |---------|/|--------(Q0.0)-----|
M0.0 i M0.1
i
---| |---
Q0.0
|---| |---------||--------(M0.1)-----|
Q0.0 i I0.0
i
---| |---
M0.1
Is This Answer Correct ? | 3 Yes | 2 No |
Answer / mahesh
[ PB M2 O/P ]
[-----[ ]--------[/]--------( )----]
[ i ]
[ O/P i ]
[-----[ ]---i ]
[ ]
[ PB O/P M1 ]
[-----[/]----[ ]-------------( )---]
[ ]
[ PB M1 O/P M2 ]
[-----[ ]----[ ]-----[ ]-----( )---]
[ ]
Is This Answer Correct ? | 2 Yes | 1 No |
Answer / suresh
Hello friends tray to understand the question,
Only use the single push button, from above every answers are giving to no.of switches, and hear require only on push button, so i think hear use the + edge trigger and - edge trigger in parllel
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / plc
first put a pb and connect an output, latch that circuit
with that output, to turn off form a exor logic using the
input as pb and connect the output with nc switch in the
first circuit.
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sunil
here You will get complete answer to question
One push button to on and off motor with ladder program
http://plc-scada-dcs.blogspot.com/2012/04/push-to-on-push-to-off-plc-program.html
enjoy.....
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / sara
|---| |---------|/|--------(M0.0)-----|
I0.0 i M0.1
i
---| |---
M0.0
|---| |---------|/|--------(Q0.0)-----|
M0.0 i M0.1
i
---| |---
Q0.0
|---| |---------||--------(M0.1)-----|
Q0.0 i Q0.0
i
---| |---
M0.1
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / mahesh m
on and off using single push button
[----||---i---|\|-------------( )---]
[ PB i M1 O/P ]
[ i ]
[----( )---i ]
[ O\P ]
[ ]
[----||---||-------------------( )--]
[ O\P PB M1
[
Is This Answer Correct ? | 0 Yes | 1 No |
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