how to caluculate APFC panel rating, my running Load is
1320KW, Present P.F 0.76 to 0.8 we need 0.98 p.f
Answers were Sorted based on User's Feedback
Answer / ak
KVAr = KW(multiplication factor )
1320(tan@1-tan@2)
cos@1-intial P.f
cos@2-final P.f
kvar=1320(0.541)
Kvar=715
| Is This Answer Correct ? | 120 Yes | 19 No |
Answer / anjaneyulu
we required runnig load and maximum demand also
then only we will get perfect KVAR
| Is This Answer Correct ? | 53 Yes | 11 No |
Answer / deniram anandrao nikhare
KVAR Required = Operating KW x [Tan (A1) - Tan (A2)]
Where A1 = Inverse Cosine of present power factor
= Cos-1(0.78)
= 38.739
A2 = inverse Cosine of desired power factor
= Cos-1(0.98)
= 11.478
Tan(A1)=Tan(38.739)=0.8022
Tan(A1)=Tan(11.478)=0.2030
Hence,
KVAR Required=1320 x (0.8022-0.2030)
SO KVAR NEEDED TO ATTACHED=790 kVAR
| Is This Answer Correct ? | 38 Yes | 4 No |
Answer / ytd
Please refere Capacitor manufacturers catlogue where there
is table to improve PF Vs. Load.
| Is This Answer Correct ? | 55 Yes | 38 No |
Answer / ajeet singh
Input Initial Power Factor : .76
Input Desired Power Factor: .98
Input Load KW (KW) : 1320 KW
SO KVAR NEEDED TO ATTACHED :860 KVAR IF U WANTS .98
KVAR NEEDED TO ATTACHED :940 KVAR IF U WANTS .98
THESE 2 PANELS U NEED TO BE INSTAL ON THIS CONNECTED LOAD
AND ALSO DEMAND WILL GO DOWN
VISIT: www.sigmacontrols.net
| Is This Answer Correct ? | 23 Yes | 9 No |
Answer / santosh
please give the details how much is your inductive load (
motor ) or give the connected load list & presently
connected capacitor.( kvr)
| Is This Answer Correct ? | 14 Yes | 3 No |
Answer / tejas doli
CHECKED THE WHOLE DAY LOAD CACLULATION
CHECHED THE KVARH, KVA, KWH READING
| Is This Answer Correct ? | 12 Yes | 8 No |
Answer / ajay sharma
290 kvar panel of 14 stage
conected relay {fifo}
| Is This Answer Correct ? | 8 Yes | 4 No |
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