Answer / maprayil

KVAr is square root of (KVA2-kW2). In your case the system KVAr at P.F. 0.76 lag is 1129 KVAr; and P.F. 0.80, it is 990 KVAr. (These are the KVAr values required to take your system P.F. to Unity or 1.00). Please note the following values:-

With a running load of 1320 kW, the Maximum Demand (KVA) of your system at 0.76 PF is 1737 KVA; and at P.F. 0.80, it is 1650 KVA. At a P.F. of 0.98, the Max Demand would be 1347 KVA (KVA = kW/P.F.).

Now that you have the system KVAR & KVA values, the simplest way is to calculate the system KVAR after P.F. is improved to 0.98 lag (your desired value). This can be worked by (considering initial P.F. 0.76):-

KVAR = Square root ((KVA+kW)*(KVA-kW))
= Square root ((1347+1320)*(1347-1320)
= Square root (2667 * 27) = SQRT 72009
= 268 KVAr.

So KVAR required for improving the P.F. of 1320 kW running load from 0.76 to 0.98 is 1129 KVAR (initial system KVAR) minus 268 KVAr (final system KVAR), i.e., 861 KVAr. This KVAR needs to be installed in multiple steps with automatic switching arrangement.

Answer / manish mangla

Actually it is very simple.You know the present pf and
desired pf too.so you can use the formula:

Kvar=kwh(tan(inverse)phi1-tan(inverse)phi2)

Phi1=actual or present pf
Phi2=desired pf

Answer / s. k. mishra

KVAR^2 = KVA^2 - KW^2 = KVA^2 - KVA^2 * pf^2= KVA^2(1-pf^2)

THEREFORE KVAR= KVA [(1-pf^2)]^1/2

Answer / tajinder singh

kw=1320
present PF = 0.76
kva =1320/0.76
=1737
for unity pf u require capacitors Panel =1129 kVAr
for 0.98 pf u require capacitors panel =858 kVAr

Answer / vijay kumar

APFC panel rating = 400 KVAR

Answer / vijay

Kvar=KVA(1-P.F)
KVA=KW/P.F
Kvar=Kw(1-P.F)/P.F
=1320(1-0.98)/0.98
=250

Answer / cibi

by using delsigma relations or fiuys charts apf panel rating
could be determined

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