Answer / tarun aggarwal

when no rotor is the opposing flux will not introduced and
as reluctance of the ckt will be small a huge current will
be there resulting in burning of stator coil
opposing current is responsible for less stator
current

there will be rotating field i agree but it cant be
tolerated as reluctance is very less and current is high

Answer / vinod kumar t

an induction motor can be considered as a transformer whose
secondary is short circuited. if the rotor is taken out, it
wle be agts as a transformer whose secondary is open. hence
the motor wil draw only magnetising current which is of
very less in magnitude .

Answer / vidhya

magnetic field will be developed , but due to the absence
of the rotor no rotor flux will be produced,so no
interaction of fluxes b/w stator and rotor,so no torque
will be produced and thus the motor remains static...ie.,it
will work like a transformer....

Answer / himanshu misra

A rotating field will be developed.

Answer / g.dharnendran

A rotating magnetic field with rated speed Ns=(120f/p) will
be produced

Answer / santhoshkumar

stator winding will get burn since there is no back emf

Answer / a.kossay

IF THE ROTOR TAKEN OUT WITH THE MAGNETIC CORE NOTHING WILL
HAPPEN, ONLY THE MAGNETZING CURRENT WILL INCREASE BECAUSE
THE MAGNETIC FIELD WILL HAVE TO ROTATE IN AIR WICH HAVE A
HIGH RELUCTANCE AND OF COURSE THE THE COIL INDUCTANCE IS
INVERSILY PROPORTIONAL WITH THE MAGNETIC RELUCTANCE SO IT
WILL BE SO SMALL RESULTING IN HIGH MAGNETIZING CURRENT

Answer / c.d.majee

magnetic field will be developed , but due to the absence
of the rotor no rotor flux will be produced,so no
interaction of fluxes b/w stator and rotor,so no torque
will be produced and thus the motor remains static...ie.,it
will work like a transformer....

Answer / x man

flux loss

which of the following elements is not present in stainless steel

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