Suppose there are two cylinders / vessels.In one cylinder
the pressure is 1.5 bar & in other 0.5 bar.If both cylinder
are connected internally through valve connection, what
will be the final pressure in both?
Answers were Sorted based on User's Feedback
Answer / fat cat
I'm guessin 1 bar. Because the pressure will equalise.
| Is This Answer Correct ? | 36 Yes | 5 No |
Answer / akash varshney
we know that total .no of moles should be constant,
now-
_ _
p1v1=n1RT1 p2v2=n2RT2
now-- after mixing.
_
PV=(n1+n2)RT
from avobe two eqn....
_ _ _
PV=(p1v1/RT1 + p2v2/Rt2)RT
....PV=(p1v1/T1 + p2v2/T2)T
so now for getin the value of final pressure pwe shpuld
know the final value of T .because v=v1+v2.
now p(V1+V2)==(p1v1/T1 + p2v2/T2)T
so p=(p1v1/T1 + p2v2/T2)T/(v1+v2)
if T1=T2=T and V1=V2=V
thn ....
p=(p1v/T+p2v/T)T/(v+v)
so p=(p1+p2)/2
now p=(1.5+.5)/2
p=1 Ans.
| Is This Answer Correct ? | 26 Yes | 3 No |
Answer / sunil
pressure changes still they come to thermal eqilibrium .
final volume=v1+v2 use p*v=n*R*t=====>T=PV/NR
FINAL TEMPERATURE T=P(V1+V2)/NR
P(V1+V2)/NR= (P1V1+P2V2)/NR
FINAL PRESSURE=(P1V1+P2V2)/(V1+V2)
SO TO CONCLUDE EITHER VOLUME OR TEMPERATURE OF
VESSELES MUST BE GIVEN.
IF VOLUME OF BOTH THE VESSELS IS SAME
FINAL PRESSURE=(P1+P2)V/2V
====>P=(P1+P2)/2=1bar
| Is This Answer Correct ? | 16 Yes | 6 No |
Answer / sandeep
it will depend on temperature and volume of both the
cylinders..so we cant guess answer without these data.
| Is This Answer Correct ? | 7 Yes | 6 No |
Answer / lokwadermmm jntucep
hallow plz give d volumes of cylinders
by taking same volume
p1v1=p2v2
den easyyyyyyyyyyyyyyyy
p1=p2=1
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vivek
1 BAR coz after connect net
pressure in opposite will be
equal so no movement of gas
will be there after reachng 1
bar..this is equilibrium state.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / rakesh swami
Assuming the initial temperatures to be different and the cylinders (and valve, piping too) to be insulated, we can put entropy condition,i.e., overall entropy is zero for reversible adiabatic process, and get final temperature. Now all we need to do is to get final pressure by using ideal gas law PV=mRT, m=m1+m2, V=V1+V2.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / abel
It will depend on the relative volumes of the cylinders.
| Is This Answer Correct ? | 4 Yes | 5 No |
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