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Explain the method of determining maximum differential pressure during hydro testing of shell and tube heat exchangers?


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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.28 : In the development of a small engineering facility for biochemical processing, completed contract method is applied in its construction accounting. In a short contract period, let the (contract price) = A. Let the (costs to date) = B; (estimated cost to complete) = C. (a) Find the values of : (i) estimated total costs; (ii) total estimated profit; (iii) percent completion to date. (b) If the project contract is 100 % completed : (i) find the total gross profit recognized; (ii) what is the exact numerical value of C?

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When should one be concerned with the tube wall temperature on the cooling waterside of a shell and tube exchanger?

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Question 109 - (a) Acceptable wavefunction in quantum mechanics in the range of : negative infinity < x < positive infinity, vanishes at least at one boundary. Which of the following is the wavefunction or are the wavefunctions of acceptable theory : P = x, P = | x |, P = sin x, P = exp (-x), P = exp (-| x |)? State the reason. (b) Let linear momentum operator P = -ih d / dz. The wavefunction is S = exp (-ikz) where i x i = -1, k and h are constants. Find the linear momentum of such wavefunction by using the term P x S.

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Question 47 - In a cylinder with a hollow, let a is outside radius and b is the inside radius. In a steady state temperature distribution with no heat generation, the differential equation is (d / dr) (r dT / dr) = 0 where r is for radius and T is for temperature. (a) Integrate the heat equation above into T(r) in term of r. (b) At r = a, T = c; at r = b, T = d. Find the heat equation of T(r) in term of r, a, b, c, d.

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Question 38 - The terminal velocity of a falling object, v is given by v = sqrt [ 4g (R - r) D / (3Cr) ] where sqrt is the square root of, g = 9.81, D = 0.000208, R = 1800, r = 994.6, m = 0.000893. The Reynold number, L is given by L = rD (v) / m. The C for various conditions are : C = 24 / L for L < 0.1; C = 24 (1 + 0.14 L^0.7) / L for 0.1 <= L <= 1000; C = 0.44 for 1000 < L <= 350000; C = 0.19 - 80000 / L for 350000 < L. Find the value of v for the situation above by trial and error, ^ is power, <= is less than or equal to.

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