Answer / kangchuentat

QUANTUM COMPUTING - ANSWER 32.5 : (a) Ba + Be = (00 + 11) + (00 - 11) = 2 (00), 00 = (Ba + Be) / 2. Bc - Bm = (10 + 01) - (10 - 01) = 2 (01), 01 = (Bc - Bm) / 2. Bc + Bm = (10 + 01) + (10 - 01) = 2 (10), 10 = (Bc + Bm) / 2. Ba - Be = (00 + 11) - (00 - 11) = 2 (11), 11 = (Ba - Be) / 2. (b) (C0 + D1) (00 + 11) = C000 + C011 + D100 + D111 = (00) C0 + (01) C1 + (10) D0 + (11) D1 = (1/2) (Ba + Be) C0 + (1/2) (Bc - Bm) C1 + (1/2) (Bc + Bm) D0 + (1/2) (Ba - Be) D1 = (1/2) [ (Ba + Be) C0 + (Bc - Bm) C1 + (Bc + Bm) D0 + (Ba - Be) D1 ] = 0.5 ( Ba C0 + Be C0 + Bc C1 - Bm C1 + Bc D0 + Bm D0 + Ba D1 - Be D1) = 0.5 [ Ba C0 + Ba D1 + Bc C1 + Bc D0 + Be C0 - Be D1 + Bm (-C1) + Bm D0 ] = 0.5 [ Ba (C0 + D1) + Bc (C1 + D0) + Be (C0 - D1) + Bm (-C1 + D0) ] (Proven). The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

Question 76 - Let C% be the fractional crystallinity, Rs = density of sample, Ra = density of amorphous form and Rc = density of crystalline form. In a polymer, these unknowns could be related by the equation C% = (Rc / Rs) (Rs - Ra) / (Rc - Ra). (a) Find the equation of Rc as a function of C%, Rs and Ra. (b) Two samples of a polymer, C and D exist. For sample C, C% = 0.513 when Rs = 2.215 unit. For sample D, C% = 0.742 when Rs = 2.144 unit. Both samples C and D have the same values of Ra and Rc. Find the values of Ra and Rc in 6 decimal places.

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Any books are availble to read for industrial promotional officers exam.. Syllabus : PAPER-2 : Subject (Diploma Standard) Applied Science, Engineering and Management 1. MATHEMATICS 2. PHYSICS 3. CHEMISTRY 4. INDUSTRIAL MANAGEMENT 5. INDUSTRIAL ENGINEERING 6. COMPUTER APPLICATIONS & BASICS OF DOS, WINDOWS, UNIX, DB MANAGEMENT, DTP, CONCEPTS OF E-GOVERNANCE INCLUDING E-MAIL, E-COMMERCE, INTERNET, COMPUTER VIRUSES.

3 Answers   APPSC,

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What is the main difference between deflection and null type instruments?

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Is there any way to remove residual product left in pipes after a batch operation?

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When an expansion is joint needed on the shell side of a shell and tube heat exchanger?

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pls send me model paper of NPCIL for executive trainee. and syllabus of executive trainee 2015.

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.7 : An engineering investor purchases a $1000 bond that matures in 25 years. The coupon rate is 8 %. The purchase price is at 95 or 95 % of the par bond value. (a) What is the purchase price of the bond? (b) How much discount is enjoyed by the investor on average each year? (c) Find the income generated from coupon rate each year. (d) Find the overall interet rate or Yield to Maturity (YTM) by using the formula : YTM = [ Answer in (c) + Answer in (b) ] x 200 / [ par bond value + Answer in (a) ].

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A distillation column separates 10000 kg / hr of a mixture containing equal mass of benzene and toluene. The product D recovered from the condenser at the top of the column contains 95 % benzene, and the bottom W from the column contains 96 % toluene. The vapor V entering the condenser from the top of the column is 8000 kg / hr. A portion of the product from the condenser is returned to the column as reflux R, and the rest is withdrawn as the final product D. Assume that V, R, and D are identical in composition since V is condensed completely. Find the ratio of the amount refluxed R to the product withdrawn D. Hint : Solve the simultaneous equations as follow in order to find the answer (R / D) : 10000 = D + W; 10000 (0.5) = D (0.95) + W (0.04); 8000 = R + D.

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Which type of pneumatic control valve is used mostly Either Air to Open r Air to close the value And guys I need reason for your reason

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POLYMER ENGINEERING - QUESTION 24.2 : Let C% be the fractional crystallinity, Rs = density of sample, Ra = density of amorphous form and Rc = density of crystalline form. In a polymer, these unknowns could be related by the equation C% = (Rc / Rs) (Rs - Ra) / (Rc - Ra). (a) Find the equation of Rc as a function of C%, Rs and Ra. (b) Two samples of a polymer, C and D exist. For sample C, C% = 0.513 when Rs = 2.215 unit. For sample D, C% = 0.742 when Rs = 2.144 unit. Both samples C and D have the same values of Ra and Rc. Find the values of Ra and Rc in 6 decimal places.

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Chemical Engineering Material Balance - Three hundred gallons of a mixture containing 75.0 wt % ethanol and 25 wt % water (mixture specific gravity = 0.877) and a quantity of a 40.0 wt % ethanol - 60 wt % water mixture (specific gravity = 0.952) are blended to produce a mixture containing 60.0 wt % ethanol. The specific gravity of a substance is the ratio of density of a substance compared to the density of water. The symbol of weight percent is wt %. (a) Estimate the specific gravity of the 60 % mixture by assuming that y = mx c where y is wt % ethanol, x is mixture specific gravity. Values for m and c are constants. (b) Determine the required volume of the 40 % mixture.

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