Chemical Engineering Energy Balance - Please match the term A - E as follow with the stated definition : A. Yield. B. Selectivity. C. Relative saturation. D. Molal saturation. E. Absolute saturation. i. Answer : ? (moles of desired product formed) / (moles that would have been formed if there were no side reactions and the limiting reactant has reacted completely). ii. Answer : ? (moles of desired product formed) / (moles of undesired product formed). iii. Answer : ? (relative humidity 40 % means partial pressure of water vapour equals 4 / 10 of the vapour pressure of water at the system temperature). iv. Answer : ? (moles of vapour) / (moles of vapour dry gas). v. Answer : ? (mass of vapour) / (mass of dry gas).

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.24 : (a) The net present value of an engineering project is given by V. Let Q = summation of [ T / (1 + I) ^ N ] from N = A to N = B, where P = project cost, T = tax inflow, N = duration. If V = P + Q where P = -$1000, T = $275, I = 0.12 (means 12 % , capital cost of project per year), A = 1 year, B = 5 years, calculate the value of V. (b) The present value tax shields are W = $ (11.9725, 9.1486, 6.5579, 4.1811, 2.0005) in 5 beginning balances of an engineering project. Find the adjusted present value of the engineering project X, when X = V + (summation of the values of W).

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How to calculate the quantity of steam lost due to pinhole leak in a steam line of known pressure and line size?

1 Answers   CPCL,

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How can one estimate how the friction factor changes in heat exchanger tubes with a change in temperature?

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At 150 degree Celsius, a mixture of 40 wt % Sn and 60 wt % Pb present, forming phases of alpha and beta. Chemical composition of Sn at each phase : CO (overall) : 40 %, CA (alpha) : 11 %, CB (beta) : 99 %. (a) State 2 reasons for the existences of alpha and beta phases for the mixture of Sn – Pb at 150 degree Celsius. (b) By using Lever Rule, calculate the weight fraction of each phase for alpha, WA = Q / (P Q) and beta, WB = P / (P Q) where Q = CB – CO and P = CO – CA.

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is petroleum a mixture of hydrocarbon?

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what is the hearth and arch pressure in furnace?

0 Answers   IFFCO,

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ENGINEERING ECONOMY - EXAMPLE 7.2 : In the purchase of a machine with a period n = 8.5 years, the minimum attractive rate of return, i = 12 %, the cost P = $55000, F = $4000 is the salvage, annual maintenance A = $3500. The return of the investment or equivalent uniform annual benefit is $15000. The equivalent uniform annual cost is P (A / P, i, n) + A - F (A / F, i, n). The investment is considered acceptable only when equivalent uniform annual benefit is greater than the equivalent uniform annual cost. From the compound interest table, (A / P, i = 12 %, n = 8 years) = 0.2013, (A / P, i = 12 %, n = 9 years) = 0.1877, (A / F, i = 12 %, n = 8 years) = 0.0813, (A / F, i = 12 %, n = 9 years) = 0.0677. Prove by calculations whether the investment above is acceptable.

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Which chemical is used as antiscalent in RO water treatement plant?

3 Answers   Dalkia, Power Plant,

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What is load?

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diffirance between heat transfer & thermodynamics

3 Answers   Shinsung Petrochemicals,

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In a crusher where is the energy provided to it is used up for?

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