Answer / s k majumder

Meter Cubic wet volume = 1*1.52 =1.52 Meter Cubic dry vol.
= 1.52*35.33=53.70 cft

Hence for M-20 where nominal portion 1.1.5.3
Total volume comes to (1+1.5+3)= 5.5

Therefore Dry volume for one cubic meter.
Cement= 53.70/5.5=cft= 9.76cft= bag= 7.81 bag=8 bags
sand = 9.76*1.5=14.64 cft
stone = 9.76*3=29.28 ct

Answer / banti kumar

The dry volume of concrete is 15.2 for 10m³ of concrete.
The ratio of M20 is 1:1½:3
Therefore 1+1½+3 =5.5
Now 15.2÷5.5=2.76 say 2.8cum

Sand =2.8×1½=4.8 cum
Coarse aggregate=2.8×3=8.4cum
No of cement bags =2.8÷0.035=80 bags(10m3)
Therefore for 1m3 80÷10= 8 bags.

Answer / z.m mughal

M20 = 1:1½:3
Wet concrete = 1 cum
To convert wet to dry material of concrete, we multiply 1.54. (Note 1.54 is for concrete but if we calculate dry material of mortar, we will multiply 1.27)
1*1.54=1.54 cum (dry material)
Formula of material is
Ratio/sum of ratio * total material quantity
Sum of ratio = 1 1½ 3 = 5.5
Total material quantity = 1.54 cum

Cement, 1/5.5 * 1.54 = 0.28 cum
0.28/0.0354 = 7.909 bags , say 8 bags
(Note: 0.0354 is volume of 50kg cement bag in cum and 1.25 in cft).

Sand or fine aggregate, 1.5/5.5 * 1.54 = 0.42 cum

Coarse aggregate, 3/5.5 * 1.54 = 0.84 cum.

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