Answer / snigda

Absolute Volume Method - 1:4:7
Material Wt of material per bag of cement Specific Gravity Calculation Absolute Volume of material
Cement 50 Kgs 3.15 50/(1000*3.15) 0.016
Fine Aggregate 200 Kgs 2.65 200/(1000*2.65) 0.075
Coarse Aggregates 350 Kgs 2.8 350/(1000*2.8) 0.125
Water 25 lts 1 25/(1000*1) 0.025
0.241
Assuming 1% air content 0.00241 Total absolute volume 0.244

Cement per cum of concrete 1/0.244 4 bags/ cum 205 kgs 0.14 cum
Sand per cum of concrete 4/0.244 16 bags/ cum 820 kgs 0.51 cum
Coarse aggregate 7/0.244 29 bags/ cum 1434 kgs 0.80 cum

Answer / mkumar

ratio 1:4:7,
sum= 12
total vo. of ingredient of using= 1.57
1x1.57/12=0.1301m^3

0.00013x1440=0.1883kg

0.1883/50 =0.0037bags cement

sand- 4x1.57/12= 0.5233m^3

aggregate- 7x1.57/12= 0.9158m^3

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