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what do you mean by PF correction. A motor is rated at 15
kw,415 volts, 0.7 pf and eff of 0.92. The powerfactor is
improved to 0.98 by adding capacitors at the bus. calculate
the current drawn by motor under full load condition before
and after pf correction
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Answer / gk
Full load condition means rated power of 15 kw
condition.And P=VICOSQ. where v assumed to be maintained at
415v from terminal.So ICOSQ is constant to maintain rated
15kw(= (V)*(ICOSQ)) full load. Therefore if PF is improved,
current drawn by motor from supply mains will be reduced.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / k.prakashchandra
You are connecting cap between motor and supply tapping
point. So, the first answer is correct . Current drawn by
motor and the feeder remains the same.There will be
reduction in current in the bus bar
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / lakshmi
pf correction means power factor improvement. for higher
factor the cutrrnt is reduced there by decresing the losses
and incresed efficiency occurs.
input power = output power / efficiency
I/p = 15000/0.92
= 16304.34 watts
I = p/ (1.732 * v * cos(phi))
= 16304.34/(1.732 * 415 * .7)
= 32.404 Amps before pf correction
I = 16304.34/(1.732 * 415 * 0.98)
= 23.416 Amps After pf correction
from the above values we said that the factor is improved
from 0.7 to 0.98 the current will be reduced from 32.404 A
to 23.146 A respectively.
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / technicalarticlessbsvbsbsvb
No change. whatever was at rated pf will continue to be
drawn
| Is This Answer Correct ? | 2 Yes | 5 No |
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