Answer / anpu

current will get reduce

Answer / gk

Full load condition means rated power of 15 kw
condition.And P=VICOSQ. where v assumed to be maintained at
415v from terminal.So ICOSQ is constant to maintain rated
15kw(= (V)*(ICOSQ)) full load. Therefore if PF is improved,
current drawn by motor from supply mains will be reduced.

Answer / k.prakashchandra

You are connecting cap between motor and supply tapping
point. So, the first answer is correct . Current drawn by
motor and the feeder remains the same.There will be
reduction in current in the bus bar

Answer / lakshmi

pf correction means power factor improvement. for higher
factor the cutrrnt is reduced there by decresing the losses
and incresed efficiency occurs.
input power = output power / efficiency
I/p = 15000/0.92
= 16304.34 watts
I = p/ (1.732 * v * cos(phi))
= 16304.34/(1.732 * 415 * .7)
= 32.404 Amps before pf correction

I = 16304.34/(1.732 * 415 * 0.98)
= 23.416 Amps After pf correction

from the above values we said that the factor is improved
from 0.7 to 0.98 the current will be reduced from 32.404 A
to 23.146 A respectively.

Answer / technicalarticlessbsvbsbsvb

No change. whatever was at rated pf will continue to be
drawn

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