Answer / satish

Assay of Conc. HCl is 35%
Density of Conc. HCl is 1.18
Molecular Weight of HCl is 36.46

Normality=35x1.18x10/36.46
=11.3
Then apply V1N1=V2N2
V1X11.3=1000X5
V1=442.5mL
442.5 mL Of Con HCl is taken in 1000ml of water for 5N HCl.

Answer / gokul charan

For 1 normality of HCL we will take 85ml of con.HCl make
up to 1000 ml with water.

Like that for 5 normality of HCL
5*85=425ml of con HCL make up to 1000 ml with water

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