dear friends,
we are use 130 hp load run with 0.98 power factor ( 38KVAR
capacitor connected ). if we need improve the the power
factor to 1 (unity). how much kvar capacitor to be add. have
any formula? please share with me.
Answers were Sorted based on User's Feedback
Answer / jitendra
130*746=96.98kw
kvar=kw(tan pi1-tan pi2)
kvar=96.98(.2030-0)
= 19.68 Kvar
Is This Answer Correct ? | 5 Yes | 1 No |
Answer / bmk mughal
KW=96.98
COS-1.98=11.470
TAN11.470=KVAR1/KW
KVAR1=19.69
COS-11=00
TANO0=KVAR2/KW
KVAR2=0
Required KVAR=KVAR1-KVAR2
=19.69KVAR
Is This Answer Correct ? | 1 Yes | 0 No |
if u can get P.F= 1 u will get noble prize
Is This Answer Correct ? | 0 Yes | 1 No |
My question is whether bellow formula is correct to find bus size for 46kA for 0.5 second & what is RT in bellow formula. formula to calculate the size of busbar to withstand the thermal stresses due to currents with duration of 0.2 sec to 5 sec. Sp = RT( I x I x t) / K Where Sp – is the cross sectional area of bus bar in millimeters. I - is the value of AC fault current. t - is the operating time of disconnecting device in seconds. K – is the factor depending on the material of the conductor, insulation and initial and final temperature. Value of ‘k’ for copper is 143.
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