Answer / pravat

Volume=π/4 {Ld^2+0.4N(D^2-d^2)(D-d)}
Where d=dia of pile
D=dia of under ream
L=length of pile
N= no of under ream.
This the formula for pile with any no of under reams.

Answer / amit kumar sachin

Rcc Volume of 2no. Bulb (without pile rcc)
Formula = π/4 {0.4N(D^2-d^2)(D-d)}
Where d=dia of pile
D=dia of under ream(bulb)
N= no of under ream.

Calculation-
Dia of bulb(D)= 2.5 times of dia of pile
D=2.5×0.30 =0.75m
Rcc volume= π/4 {0.4×2×{(.75)^2-(.30)^2}(.75-.30)
= 0.133 m^3

Answer / h kumat

Volume of pile = A
= 3.14×(0.30/2)²×10=0.707m³


Volume of two undeream = B
=2× 2.44(0.30)³=0.13 m³

Totol volume of pile & underream=A+B
=0.707+0.13= 0.837m³

Be sure about shape of underream before use this formula.

Answer / dr. maninder singh khalistani

Volume of underream=2*3.14*.3*.3*.3/6=. 028m3

Answer / gopi

(3.14*0.3*0.3/4)*10=0.7065m3

Answer / saideepak nagajjanavar

Pile length- 10 m
Pile dia- .15m
10X.15X.15=0.225
0.225X3.142=0.7069
Ans:07069

Answer / aman kumar

Length of bulb=0.55 m
Dia. of bulb=2.5*0.3=0.75 m
Extra for bulb=0.75-0.3=0.45 m
Bulb volume= Area*Perimeter=1/2*0.55*0.225*3.14*0.3=0.058 cum for 1 bulb.
Pile volume=3.14/4*0.3*0.3*10=0.707 cum
So, For 1 bulb,Total quantity=0.707+0.058=0.765 cum
And For 2 bulb,Total quantity=0.707+2*0.058=0.823 cum

Answer / lisy rajan

Quantity of concrete= 2* 3.14*.15*.15*10=1.413m3
(with out deducting steel)

Answer / bharath m,+91 8438238335/99806

2 Under-reamed cast in situ pile of 300 mm dia. of 10.00 m
length.
Solution :
(Pls. refer construction practice book & IS 2911 Part-III.)
2 under reamed pile means there are 2 Nos. of bulbs at particular spacing based on friction of soil.

Dia. of pile : 0.30 m. ie.,bulb dia. = 2.5 times dia. of pile
So it is 2.5*.3 = .75 m.
Length of Pile = 10.00 m.
Bulb thickness at pile intersection end (30-45degree inclination)= 1.75 times pile dia.
=1.75*.3
=0.525 m. &
free end = dia. of pile/4
=.3/4
=0.075 m.
Now follow the calculation:
Step 1:
Pile volume = Area x length
3.14/4*dxd x length
=3.14/4*.3*.3*10 = 0.707 Cubic Metre. ------1

Extra for Bulb Volume = Perimeter x Depth of bulb
=2*3.14*r x db
r at centre line of bulb = ((.75-.3)/2)+.3 = 0.525 m.
V=2*3.14x .525x(.525+.075)/2
=0.989 Cum. for 1 Bulb
V for 2 Bulb = .989*2
=1.978 Cubic metre -----2

Now combined Total Volume of Concrete 1+2 = .707+1.978 = 2.685 Cubic Metre.

Answer / sai

steel should be subtracted from 7065 let it be 1 percent 7065-70.65=6994.35

what is thumb rule exactly?

2 Answers  

wha is frog?

6 Answers   SSC,

which software is better for design and analysis of buildings (stadd pro ) or (Etabs)

0 Answers   CCCL,

What the advantages and disadvantage of using 90mm and 100mm bricks for a wall of a house? Thanks for any input.

0 Answers  

How to findout safe bearing capacity after stabilization of soil by method of the confinde method.

3 Answers  

what is the crushing strength of good building stone

1 Answers  

Design a reinforced concrete combined footing (rectangular) for two columns located 3.60 metres apart. The overall sizes of the columns are 40cm x 40cm and 69cm x 60cm and the loads on them are 1000 kn and 1500 kn respectively. The space available for the width of the footing is restricted to 180cm. The S.B.C. of the soil is 280 kn/mm2 use M15 concrete.

0 Answers  

one steel fixers how much ton steel fabrication he will do same how much tone he will binding?

0 Answers   PN, Simplex,

What is the shelf life of a refractory used in boiler furnace ?

4 Answers   Monster,

what is the real de-shuttering time for rcc column,slaband wall

3 Answers  

What is full form of SNF base in concrete mix design for admixture percentage?

2 Answers  

why we providing 40mm cover to columns & 25mm to shear wall

1 Answers   NCC,