Answer / er.harjinder singh

Exp:-length of wall=10ft
Bredth of wall=4.5in
Height of wall=9.5ft
Qty.10*0.375*9.5=35.625cft
Provide .5in morter in each line of bricks.
So,first calculate qty.of mortar in total work with following steps:-
Step-1. Calcuate qty. of mortar in one line
of bricks:-
10*0.375*0.0625=0.2344cft.
Step-2. Calculate nos. of lines of bricks in given height:-
9.5/0.292=32.53 or 33bricks.
Step-3. Calculate qty. of mortar:-
33*0.2344=7.73cft.
So,Total brick work:-
35.625-7.73=27.895cft
Net. Qty. of bricks=
27.895/0.0703=396.8bricks
say 397 bricks

Answer / sidhaant gupta

cement = 1*0.3/7*1440 = 61.71 kg or 1.234 Bags
sand = 9.08 Cft
Bricks = 451 Nos

Answer / md gyasuddin ahsan

Sorry For above Answer

By Analysis of Rate-2007

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

Sand = (.22/(1+6))*6 = 0.189cum
= 0.189* 35.29 = 6.655 Cft

Answer / shahvez

By Analysis of Rate-2007

#Bricks of class designation 7.5 in foundation and plinth
in :-
Brick with wastage = 494
Mortar = .25
Cement Ratio is 1:6, then
Cement=(.25/(1+6))*1 = .0357 cum
Cement in Bags = .0357/.034722 = 1.0286 bags

Sand = (.25/(1+6))*6 = 0.2143 cum
= 0.2143 * 35.29 = 7.56 Cft
# Bricks of class designation 7.5 in superstructure above
plinth level up to floor V level in all shapes and sizes
in:-
Brick with wastage = 494
Mortar = .22
Cement Ratio is 1:6, then
Cement=(.22/(1+6))*1 = .03143 cum
Cement in Bags = .03143/.034722 = 0.905 bags

Sand = (.22/(1+6))*6 = 0.189cum
= 0.189* 35.29 = 6.655 Cft

Answer / salman

depends upon brick size

Answer / prithvi

For 1cubic meter:
No.of bricks with motar is 392 but say 400,
Cement is 1.5 bag,
Sand is 0.23 to 0.275 depends on motar ratio,generally we consider 0.26cu.m of sand

Any doubts please contact on watspp to 9010557759

Answer / aamu

Generaly we cosidered as a wall of thickness of 9"
Then when we calculate no. of brick per sq.ft. then we should consider above thick.
let cal. no.of brick/sqft = (12"x12"x9")/(8.5"x5.5"x3")
=9.240
Then if we add thck of mortar 1/2"(12cm) no.of bricks= 9.010
Total no of bricks in one brass
= 10x10x9
=900
and also add 5%wastage.

Answer / asmita balkhande

19*9*9=550
20*10*10=500

Answer / arunava singha

brick size in meter=.23*.115*.075 =.0019
add 10 mm mortar for ech sides=(.24*.125*.085)=(.0025)

bricks required for 1 m3 =(1/(0.0025)=400 nos

mortar required =(.0025-.0019)*400=.24

add 15% for wastage = (.24*1.15)=.276m3

so required sand is =.276 m3

cement is =(1440/6)=240*.276= 66 kg

Answer / sulaiman

volume of 1 brick = 0.2286*0.1143*0.0762= 0.00199103 cum
consider 1" thick mortar on either sides

volume of 1 brick with mortar = 0.2413*0.127*0.0889= 0.00272435 cum
No of brick work for 1 cum with mortar = 1/0.00272435 = 367 bricks
No of bricks without mortar for 1 cum= 1/0.00199103 =503 bricks

volume of mortar = (0.00272435-0.00199103)*367= 0.269 cum

volume of mortar in dry condition= 0.269*1.33= 0.358 cum

Cement required= 0.358*1/7*1440= 73.64 kg= 1.473 bags

sand required= 0.358*6/7*35.3357= 10.84 cuft

Reinforcement details at hinged joint

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