Answer / pramit dutta

i think the question is incomplete ,
we know n=(1-s)ns , so, ns=(120*50)/4=1500 rpm.
so we need to know the slip of motor then we find answer.

Answer / lolipop

Answer is d.) as it looks more nicer and more lengthy

Answer / netserab

first v 120f/p i.e. when 120 constant
f given ferquency
p is number of poles


then we have 4 poles on the sator and 6 poles on the
roter 120x50/3/2=1000

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