a 3 phase slip ring induction motor is wound for 4 poles on
stator and 6 poles on rotor; when 3 phase balanced voltage
source at 50 hz is applied to motor it will run at
a)1500rpm b)1000rpm c)750 rpm d)zero rpm
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Answer / pramit dutta
i think the question is incomplete ,
we know n=(1-s)ns , so, ns=(120*50)/4=1500 rpm.
so we need to know the slip of motor then we find answer.
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Answer / lolipop
Answer is d.) as it looks more nicer and more lengthy
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / netserab
first v 120f/p i.e. when 120 constant
f given ferquency
p is number of poles
then we have 4 poles on the sator and 6 poles on the
roter 120x50/3/2=1000
Is This Answer Correct ? | 1 Yes | 3 No |
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