why 1.25 factor is to be multiplied to cylindrical strength
of concrete while getting the equvalent cubical strength of
concrete?
Answers were Sorted based on User's Feedback
Answer / gaurav
1.standard cube has a ht/width ratio of 1 and std cyl has
the same ratio of 2 . cube registers a higher compressive
str than cyl which is approx 1.25 times more hense the
multiplications .
Is This Answer Correct ? | 16 Yes | 8 No |
Answer / abhijit sane
Acube has height to width ratio of 1. Hence, slenderness
does not play any role and a s a result the compressive
strength is on higher side for a cube.
In case of cylinder the slenderness comes into picture and
as a result the compressive strength is on lower side.
Hence we multiply by 1.25 to get a realistic picture
Is This Answer Correct ? | 6 Yes | 1 No |
Answer / b.srinivasarao
generally cylindricalstrength is equalto cube strength,
when cylender height to dia. ratio is 2:1, because
correction factor for cylindrical strength is
f=0.11n+0.78, where n=HEIGHT OF CYLINDER/DIA.OF CYLINDER.
SO IF H/D RATIO VARIES CORRECTION FACTOR ALSO VARIES
Is This Answer Correct ? | 4 Yes | 1 No |
Answer / umair majeed
Governing factor of application of such factor is h/d ratio of both the cube and cylinder specimens. As h/d ratio increases, strength decreases. h/d ratio of cylinder is twice to that of cube. Moreover, when load is applied on cube specimens, compression imposed by platens of testing machine enhance the confinement which in turn increases the compressive strength of cubes. It is reported that for 3000psi concrete, ratio of strength of cylinder to that of cube is around 0.76. Hence whenever cube strength is taken as multiple of cylinder strength then a factor of 1.25 is incorporated to get approximate results.
Is This Answer Correct ? | 1 Yes | 0 No |
due to less height there is an overlapping in end friction in cubes. the end friction effect is up to 0.8*base dimension for each face which gives 0.6*L overlapping
but cylinder have double height than base dimension which will eventually stops from end friction overlapping.
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / venkat
i feel it is shape factor which is multiplying there, but i
want the answer in detail for this question... somebody
please help me...
Is This Answer Correct ? | 7 Yes | 8 No |
Answer / vipin nath
I is the sigma factor that is multiplied to get the
equivalent cubical strength of concrete
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / eng. ali
Because of the overlap in the cracks of the cylindrical
sample,With the knowledge that the two samples have the
same ratio.
Is This Answer Correct ? | 0 Yes | 1 No |
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