Answer / pillay

The current drawn depends on the power consumed by the motor
and the operating voltage.
KW =1.72 X VL X IL X PF
Now assuming both the motors are loaded at 100 kw each OF PF
0.8 than the 6.6kv motors current consumption will be
100000KW /1.72 X 6600 X 0.8 =11 AMPS
If 415 volts is used than
100000 / 1.72 x 415 x 0.8 = 175 AMPS.

Answer / natarajan

answer is corret

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