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How many bytes will be allocated for the following record
description
entries?
01 REC-A.
05 A PIC S9(4).
05 B PIC XXXBXXX.
05 C PIC ____9.99.
05 D PIC S9(5) COMP-3.
05 E PIC 9(3) COMP.
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Answer / suresh kumar
total 19 bytes, For furtyher expansion you can see deepaks
answer.
| Is This Answer Correct ? | 1 Yes | 6 No |
Answer / asif
05 A PIC S9(4). = 4
05 B PIC XXXBXXX. = 7
05 C PIC ----9.99. = 8
05 D PIC S9(5) COMP-3. = 3
05 E PIC 9(3) COMP. = 2
LENGTH OF REC-A = 24 BYTES.
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / guest
Folloiwng will be space allocation:
A - 4
B - 7
C - 8
D - 3
E - 2
Total 24 bytes.
| Is This Answer Correct ? | 2 Yes | 8 No |
Answer / guest
correct answer is 25 bytes.. since s9(5) comp-3 will take 4
bytes.. not 3 bytes
A-4
B-7
C-8
D-4
E-2
| Is This Answer Correct ? | 0 Yes | 11 No |
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COBOL 
