can any one tell me the formula for calculating the power
and unit consumpetion
Answers were Sorted based on User's Feedback
Answer / mubashar ali
total KW * total runing Hours= unit
for example
5 lamp 100 watt each onload for 6 hour
AC 3000W onload for 3 hour
Motor 5HP (5*746=3730W) onload for 2 hour
than
500/1000 * 6= 3
3000/1000 * 3= 9
3730/1000 * 2= 7.46
total unit = 19.46 * Rs.
Is This Answer Correct ? | 12 Yes | 0 No |
Answer / ramesh gaur
one unit is equal to one kwh(1000w per hour)
Is This Answer Correct ? | 8 Yes | 0 No |
Answer / vinothbabu.k
P=(1.732*VOLTAGE*AMPS)/1000,
FOR UNIT CONSUPTION:
KWATTS*HOURS=UNIT-ITS FOR INDUCTIVE LOAD,
FOR RESISTIVE LOAD THE ABOVE IS CORRECT,LAMP HEATER IS
RESISTIVE LOAD,
IT DEPANDS ON TYPE OF LOAD.
AND FOR CAPACITIVE & INDUCTIVE LOAD NO OF WORKING HOURS
WILL BE VARRY,FOR EXAMPLE TAKE FRIDGE WAS WORKING FOR 2
HOUR IT TAKE 750W MEANS WE SHOULD NOT
CALCULATE .750*2=1.5KWHR/UNIT,FRIDGE IS A CAPACITIVE LOAD
IT WILL ON OPPROXIMATELY 35 MIN FOR EVERY PER HOUR SO WE
SHOULT TAKE FOR 2 HRS IT WILL ON 1.05HRS FOR 2 HRS,
SO 750*1.05=0.787 UNIT
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / mad sarfaraj
power(p)=dw/dt(this is the basic formula 4 power)
and it's S.I. unit is joule/second or watt.
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / balaji
Power=i^2*R(resistor multiplied with square of current)
Is This Answer Correct ? | 0 Yes | 0 No |
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