ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.24 : (a) The net present value of an engineering project is given by V. Let Q = summation of [ T / (1 + I) ^ N ] from N = A to N = B, where P = project cost, T = tax inflow, N = duration. If V = P + Q where P = -$1000, T = $275, I = 0.12 (means 12 % , capital cost of project per year), A = 1 year, B = 5 years, calculate the value of V. (b) The present value tax shields are W = $ (11.9725, 9.1486, 6.5579, 4.1811, 2.0005) in 5 beginning balances of an engineering project. Find the adjusted present value of the engineering project X, when X = V + (summation of the values of W).
ACCOUNTING AND FINANCIAL ENGINEERING - ANSWER 34.24 : (a) Let ^ to be mathematical symbol for power. From N = A = 1 year to N = B = 5 years, Q = summation of [ T / (1 + I) ^ N ] = T { summation of [ (1 + I) ^ (-N) ] } = $275 { summation of [ (1.12) ^ (-N) ] } = $275 [ (1.12) ^ (-1) + (1.12) ^ (-2) + (1.12) ^ (-3) + (1.12) ^ (-4) + (1.12) ^ (-5) ] = $991.31. Then V = P + Q = -$1000 + $991.31 = -$8.6865. (b) X = V + (summation of the values of W) = -$8.6865 + $ (11.9725 + 9.1486 + 6.5579 + 4.1811 + 2.0005) = $25.1741. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.15 : Based on Time Discounting of Money, let y = x / (1 + r) ^ n, where ^ = power, r = interest rate for the period in decimal value, n = number of periods, y = current value, x = future value. According to Present Value Addition Rule, the present value of a set of future payments is equal to sum for present value of each of the payments. In an engineering business, 3 future payments are to be made : $100 after 1 year; $500 after 2 years; $200 after 3 years. (a) Form an equation of y as a function of r. (b) Find the value of y in 5 decimal places if r = 8 %.
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2 Answers Cairn, IOCL, Reliance,
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