Answer / kangchuentat

ACCOUNTING AND FINANCIAL ENGINEERING - ANSWER 34.24 : (a) Let ^ to be mathematical symbol for power. From N = A = 1 year to N = B = 5 years, Q = summation of [ T / (1 + I) ^ N ] = T { summation of [ (1 + I) ^ (-N) ] } = $275 { summation of [ (1.12) ^ (-N) ] } = $275 [ (1.12) ^ (-1) + (1.12) ^ (-2) + (1.12) ^ (-3) + (1.12) ^ (-4) + (1.12) ^ (-5) ] = $991.31. Then V = P + Q = -$1000 + $991.31 = -$8.6865. (b) X = V + (summation of the values of W) = -$8.6865 + $ (11.9725 + 9.1486 + 6.5579 + 4.1811 + 2.0005) = $25.1741. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.29 : An engineering company that produces small biochemical tools applies Installment Sales Method in its accounting. Let A = Installment Sales, B = Cost of Installment Sales, C = Gross Profit, D = Gross Profit Ratio. In year 20X8, let A = $400, B = $250, C = $150. In year 20X9, let A = $450, B = $315, C = $135. If the value of D = 37.5 % in year 20X8 : (a) find the value of D for year 20X9; (b) calculate the realized gross profit = ED / 100, for year 20X8 when the cash collected from sales is E = $100.

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ENGINEERING MECHANIC - EXAMPLE 15.3 : A biochemical trolley of mass 15 kg is towing a trailer of mass 5 kg along a straight horizontal pathway. The trailer and the trolley are connected by a light inextensible tow-bar. The engine of the trolley exerts a driving force of magnitude 100 N. The trailer and the trolley experience resistances of magnitude 10 N and 30 N respectively. (a) Form 2 equations with unknowns T and a, that represents the equilibrium for the 2 systems of the trolley and trailer. (b) Solve the simultaneous equations from the 2 equations that are obtained in part (a) of this question. T is the tension of the tow-bar and a is the acceleration.

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