Answer / amit malik

cp mistake in 1st one.
-----------------------------------

Blocking statements are executed on after another
represented by '='

Ex. lets take two variables
reg A:0;
reg B:1;
initial
begin
A = B;
B = A;
end

Ans
A = 1
B = 1

Non Blocking
instructions are executed concurrently
represented by '<='

Ex. lets take two variables
reg A:0;
reg B:1;
initial
begin
A <= B;
B <= A;
end

Ans
A = 1
B = 0

Answer / appu

@ Remya,

With non-blocking statements as shown above, A will always
get the OLD/previous value of B, and B will always get the
OLD/previous value of A.

Because, in a non-blocking statement assignment, the right
hand side of the statement gets evaluated right away, but
doesn't get assigned to the left hand side of the statement
until at the end of the time step.

Answer / amit malik

Blocking statements are executed on after another
represented by '='

Ex. lets take two variables
reg A:0;
reg B:1;
initial
begin
A = B;
B = A;
end

Ans
A = 1
B = 1

Non Blocking
instructions are executed concurrently
represented by '=>'

Ex. lets take two variables
reg A:0;
reg B:1;
initial
begin
A = B;
B = A;
end

Ans
A = 1
B = 0

Answer / darshan

DURING BLOCKING STATEMENTS, PREVIOUS VALUES GETS STORED TO
THE LHS.

WHERE AS IN NON BLOCKING STATEMENT, SINCE IT IS EXECUTING IN
PARALLEL 1ST SIMULATOR READS AND STORES IN TEMPORARY
REGISTER INTERNALLY IN SIMULATOR. THEN AT THE END OF THE
TIME UNIT IT IS ASSIGNED TO THE LHS.

ANYWAYS FROM MY POINT OF VIEW A OR B DONT GET THE PREV/OLD
VALUE

Answer / remya

Yes,the explanation is ok but after a particular time
units,the value of B must be equal to 1 no?

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