A 30KW motor running at 1450 rpm draws 56A, how would you
determine if this is correct or not?
Answers were Sorted based on User's Feedback
Answer / divakaran a
P=1.732xVxIxP.F
30KW=1.732x415xIx0.8
I=30000/(1.732x415x0.8)
I=52.17 AMPS
sO the current drawing from the motor is 52 amps (Theoriticaly)
in practical the motor may draws more current as based on the load.
Is This Answer Correct ? | 13 Yes | 2 No |
Answer / vipul kumar rai
P=1.732xVoltage x I(current )xPower Factor
30KW=1.732x415xIx0.8
I=30000/(1.732x415x0.8)
I=52.17 AMPS
as per thory 52.17A current draw.
so 56A is approx correct.
Is This Answer Correct ? | 2 Yes | 0 No |
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