Answer / anshul pal

Because these are the losses which occur in lines and cause real power loss, hence these loss can not occur in negative term. As current varies sinusoidally, the square of current will remain positive, therefore accounts to i square r loss.

Answer / md tarekul alam

Pls dear sir, answer me in this question.

Answer / anjan

copper losses nathing but heat produced.it mean that real power loss.thats why I2R

Answer / k.prakashchandra

Pd across a resistor id I(amp) x R (ohm) volts ,power is V X
I = I^2 R watt

Answer / k.prakashchandra

Read above as ' Pd V across a resistor= I(amp) x R (ohm)
volt.Power = V x I = I^2 R watt' ( As pd is measured across
the resistor ,the pf is unity)

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