What regulates, or gives a substance the viscosity it has?
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Answer / eugene
Viscosity only applies to fluids, ie. gas and liquid.
However, the nature of viscosity for gas and liquid are
different.
In general, the liquid viscosity is dependent on the
strength of intermolecular attraction. The stronger the
intermolecular attraction, the more the viscous the liquid
is.
In fact, raising the temperature of the liquid decreases
its viscosity. This reflects the viscosity of a liquid is
indeed dependent on the intermolecular attraction.
Is This Answer Correct ? | 13 Yes | 0 No |
Answer / chem
As we know what is viscosity is
Viscosty is the resistance offered in the motion of fluid.
it is the ratio of the shear stress and velocity gradient
so it depends on the following factors
shear stress
temperature
velocity
Is This Answer Correct ? | 9 Yes | 2 No |
Answer / shrinivas prasad bulusuwar
viscosity is basically the resistance to flow, caused by
friction between two adjacent layers of the fluid.
The bottommost layer offers resistance to the adjacent
layer causing decrease in the velocity of the adjacent
layer.
Also, viscosity is caused due to the inter-molecular forces
of attraction.
Is This Answer Correct ? | 6 Yes | 1 No |
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BIOCHEMICAL ENGINEERING INSTRUMENTATION - EXAMPLE 29.1 : In the application of Theory of Spectrometry in spectrophotometer, let n = N x C x V, V = A x t, e = a x N where n = number of molecules, N = Avogadro's number, V = volume of cuvette, A = area of cuvette, t = thickness of cuvette, C = concentration of fluid in the cuvette, e = extinction coefficient, a = effective area of molecule. (a) By using calculus in dI = -I x a x N x C x dt, prove that ln (I / Io) = -a x N x C x t, where dI is the small difference in I and dt is the small difference in t. I = intensity of light. Io = initial intensity of light. (b) Show by calculations that ln (Io / I) = e x C x t based on the answer in the previous question (a). (c) Find the equation of log (Io / I) as a function of e, C and t based on the answer in the previous question (b).
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