Answer / dibyendu mukherjee

For column cover is 40 mm both sides
here
600-40-40=520
400-40-40=320
For hook (10 times the dia meter of the bar)
so for 8mm = (80mm)
For bending (minus) 5X2d=5x2x8=80mm
Now the cutting length of the bar will be = 520+520+320+320+80+80-80
= 1780 mm (1.78 m)
ring size = 520 X 320

Answer / shreeram singh

For column cover is 40 mm both sides=
600-40-40=520
400-40-40=320
For hook (10 times the dia meter of the bar)
so for 8x10mm = (80mm)
For bending (minus) 5X2d=5x2x8=80mm
Now the ring size is= 520+520+320+320+80+80-80
= 1760 mm (1.76 m)

Answer / dinesh kaushik

for column cover is 40mm both side=600-40-40=520,400-40-40=320
for hook(10 times the dia of bar)so for 8*10mm=80mm
number of hook two 2*80=160mm,for bending minus 5*2d=5*2*8=80
now the ring size is 520+520+320+320+160-80=1760mm(1.76m)

Answer / madhusudhanan vellore

What is the ring size of column 600x400 (8mm dia ring) ?
For column cover is 40 mm both sides
here
600-40-40=520
400-40-40=320
For hook (10 times the dia meter of the bar)
so for 8mm = (80mm)
Ring size = 520+520+320+320+80+80
= 1840 mm (1.84 m)

Answer / bhupendra singh rajput

leaving the clear cover of 40mm from both the sides, So it will totally 80mm cover.so the ring size of 600*400 will be. So it will totally 80mm cover
520*320

Answer / abhinav

600*400 column size
Cover 40mm
So 2*(520+320 )= 1680
+ Hook length = 10d*2 = 160mm
- bend deduction= 3*2d+ 2*3d = 12d = 96mm
- bar dia (8mm)= 8mm
So 1680+160-96-8 = 1840- 104= 1736mm

Answer / prashanth

Leave the column cover example 40mm on both side

Answer / gurjant sharma

ring size outer to outer is 520 *
320
inner to inner is 504*304
40mm cover for col.

Answer / udayakumar

400-30-30-340
600-30-30=540

340+540+340+540+80=1840mm
Ring size will be 340*540+80mm(hook)to be consider

Answer / harish bisht

leave the cover from both sides and add the dia of ring on it
ex-column size 600*400 and cover is 50 mm
so ring size -508*308

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